Explanation:
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The force of attraction between 2 charged spheres can be explained by Coulomb's law,
It states the force of attraction is directly proportional to the magnitudes of the charges and inversely proportional to the square of the distance between the charges.
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where F - force of attraction/repulsion
q₁ and q₂ - charges of the 2 spheres
k - Coulomb's law constant
r - distance between the spheres
In the question given, the charges of the spheres remain constant in both instances, only distance changes. Therefore (kq₁q₂) = c which is a constant
then F = c / r²
first instance
6 x 10⁻⁹ N = c/ (20 cm)² ---1)
F = c/(10 cm)² --- 2)
2) / 1)
F = 6 x 10⁻⁹ x 4
F = 2.4 x 10⁻⁸ N
Answer:
11.34 m/s
Explanation:
Force F = 25 N
Lenght of application l = 16.5 cm = 0.165 m
Time of application t = 1 sec
Radius of wheel r = 33.0 cm = 0.33 m
Moment of inertia I = 1200 kg·cm^2 = 0.12 kg-m^2
Let us assume he rides a fixed gear bicycle so that one revolution of the pedal is equal to one revolution of the tire
Solution:
Torque T on pedal = F x l = 25 x 0.165 = 4.125 N-m
Rotational impulse = T x t = 4.125 x 1 = 4.125 N-m-s
Initial momentum of wheel = 0 (since it start from rest)
Final momentum of wheel = I x w
Where w = angular speed
I x w = 0.12w
Change of momentum = 0.12w - 0 = 0.12w
Rotational impulse = momentum change
4.125 = 0.12w
w = 4.125/0.12 = 34.375 rad/s
Tangential velocity of wheel = angular speed x radius of wheel
V = w x r = 34.375 x 0.33 = 11.34 m/s
Answer:
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Answer:
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