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3 years ago

Segment Addition Postulate : Solve for X

Mathematics

1 answer:

aleksklad [387]3 years ago

6 0

Answer:

Step-by-step explanation:

3x-6 = x+4 + 4

3x-x = 4+4+6

2x = 14

x= 7

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Please tell me if my answers are right

Ulleksa [173]

Yeah I’m PREETY sure

6 0

3 years ago

X+y+z=1

andrezito [222]

Answer: x = 0

y = 2

z = -1

Step-by-step explanation:

The system of equations are

x+y+z=1 - - - - - - - - - - 1

-2x+4y+6z=2 - - - - - - - - - 2

-x+3y-5z=11 - - - - - - - - - 3

Step 1

We would eliminate x by adding equation 1 to equation 3. It becomes

4y -4z = 12 - - - - - - - - - 4

Step 2

We would multiply equation 1 by 2. It becomes

2x + 2y + 2z = 2 - - - - - - - - - 5

We would add equation 2 and equation 5. It becomes

6y + 8z = 4 - - - - - - - - - 6

Step 3

We would multiply equation 4 by 6 and equation 6 by 4. It becomes

24y - 24z = 72 - - - - - - - - 7

24y + 32z = 16 - - - - - - - - 8

We would subtract equation 8 from equation 7. It becomes

-56z = 56

z = -56/56 = -1

Substituting z = -1 into 7, it becomes

24y - 24×-1 = 72

24y + 24 = 72

24y = 72 - 24 = 48

y = 48/24 = 2

Substituting y = 2 and z = -1 into equation 1, it becomes

x + 2 - 1 = 1

x = 1 - 1 = 0

4 0

4 years ago

PLEASE HELP ME WITH THIS I NEED IT

sukhopar [10]

Answer:

1400π m³

Step-by-step explanation:

V = BH

V = 10² * π * 14 = 1400π m³

5 0

4 years ago

Use the exponential decay model, Upper A equals Upper A 0 e Superscript kt, to solve the following. The half-life of a certai

Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

$A=A_0 e^{kt}$

Where,

$A_0$ = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = $\frac{A_0}{2}$ ,

i.e.

$\frac{A_0}{2}=A_0 e^{19k}$

$\frac{1}{2} = e^{19k}$

$0.5 = e^{19k}$

Taking ln both sides,

$\ln(0.5) = \ln(e^{19k})$

$\ln(0.5) = 19k$

$\implies k = \frac{\ln(0.5)}{19}\approx -0.03648$

Now, if the substance to decay to 78% of its original amount,

Then $A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0$

$0.78 A_0=A_0 e^{-0.03648t}$

$0.78 = e^{-0.03648t}$

Again taking ln both sides,

$\ln(0.78) = -0.03648t$

$-0.24846=-0.03648t$

$\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7$

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0

3 years ago

If f (x) = -9x - 9 and g (x) = Vx - 9, what is (f ° g) (10)?

Temka [501]

Answer: $(f \circ g) (10)= -18\ .$

Step-by-step explanation:

Given: $f (x) = -9x - 9$ and $g (x) = \sqrt{x - 9}$

To find : (f o g) (10)

For this we first find (f o g) (x)= $f(g(x))$

$=f(\sqrt{x-9})\\\\=-9(\sqrt{x-9})-9$

Now,

$(f \circ g) (10)=-9(\sqrt{10-9})-9\\\\=-9\sqrt{1}-9\\\\=-9-9=-18$

Hence, the value of $(f \circ g) (10)= -18\ .$

8 0

3 years ago

Segment Addition Postulate : Solve for X​

Segment Addition Postulate : Solve for X