3 years ago

PLEASE HELP ME WITH THIS I NEED IT

Mathematics

1 answer:

sukhopar [10]3 years ago

5 0

Answer:

1400π m³

Step-by-step explanation:

V = BH

V = 10² * π * 14 = 1400π m³

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Somebody help me with this please .

erastova [34]

Step-by-step explanation:

12. Cos 60° = 8/c

0,5 = 8/c

0,5 c = 8

c = 16

D² = V16²-8²

= V256-64

=V192 = V16×12 = 4V12

= 4V4×3 = 8V3

13. Cos 30° = 6/b

V3/2 = 6/b

V3 b = 12

b = 12/V3

b/Sin B = a /sin A

b/Sin90° = 6/ sin 60°

b = 6

1 V3/2

b× V3 = 6

b = 6× 2/V3

= 12/V3

8 0

3 years ago

Salut! |4x^2+9x-9|=0 X= ? Multumesc in avans :D

Afina-wow [57]

X=3 or -3/4.Îmi pare rău că nu mi-am arătat munca

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3 years ago

Find the value of x in given expression <img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%2024%20%2B%2025"

zepelin [54]

Answer:

$x = 7 \: or \: - 7$

Step-by-step explanation:

...............maybe

5 0

2 years ago

Read 2 more answers

Ms. Sunshine is going to bake cookies for her students. She wants each student to receive 2.5 cookies. If she has 25 students in

adell [148]

Answer:

Ms. Sunshine needs to make 62.5 cookies.

Step-by-step explanation:

25 * 2.5 = 62.5

4 0

2 years ago

A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3 4

dimaraw [331]

Given :

A patient with high blood pressure who weighs 226 pounds is put on a diet to lose 26 pounds in 3 months. The patient loses 8 3/4 pounds the first month and 11 5/8 pounds the second month.

To Find :

How much weight must be lost the third month for the goal to be achieved.

Solution :

Let, weight lose in third month is x.

So, 8 3/4 + 11 5/8 + x = 26

$\dfrac{32+3}{4}+\dfrac{88+5}{8}+x=26\\\\x = 26 - ( \dfrac{35}{4}+\dfrac{93}{8})\\\\x=5.625\ pounds$

Therefore, weight lose in third month is 5.625 pounds.

Hence, this is the required solution.

3 0

3 years ago