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3 years ago

A square classroom has a wall that is 21 feet long. What is the area of the classroom?

Mathematics

1 answer:

Rasek [7]3 years ago

6 0

<u>Answer and Step-by-Step explaination:</u>

Area =Length time Width

Area= 21*21

Area=441

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Compare 6 ⋅ 108 to 3 ⋅ 106.

djverab [1.8K]

Answer:

$6*10^8$ is 200 times larger than $3*10^6$

Step-by-step explanation:

$6*10^8\ and \ 3*10^6$

To compare both values we divide the exponents

$\frac{6*10^8}{3*10^6}$

6 divide by 3 is 2

for simplify exponents we use exponential property

a^m / a^n = a^(m-n)

$\frac{10^8}{10^6}=10^2$

$\frac{6*10^8}{3*10^6}=2*10^2= 200$

$6*10^8$ is 200 times larger than $3*10^6$

4 0

2 years ago

Read 2 more answers

jane and eric decide to drive to kansas city, as they leave home in columbia, they notice the car odometer reads 22,745 miles. W

Ksju [112]

118 miles hope it hleps

5 0

2 years ago

Fine the two consecutive whole numbers the square root is between: √(26) & √(60)

blondinia [14]

The consecutive number = 1,2 or 7,8 not 5,8 etc

whole number = 1,6,100

square root of 60 = 7.746

so, if you want to know two consecutive whole numbers b/w swrt of 60
that would be

7 less than 7.6 less than 8

3 0

3 years ago

The midpoint of \overline{\text{AB}}AB is M(-6, -4)M(−6,−4). If the coordinates of AA are (-4, -3)(−4,−3), what are the coordina

valentina_108 [34]

Answer:

The coordinates of B is (-8,-5).

Step-by-step explanation:

The midpoint of line AB is M. The coordinate of M is (-6,-4).

The coordinates of A is (-4,-3)

We need to find the mid point of B.

If M(x,y) is the midpoint of the coordinates (x₁,y₁) and (x₂,y₂). The mid point theorem is used as follows :

$M(x,y)=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})$

Let the mid point of B is (x₂,y₂). Put (x,y) = (-6,-4), (x₁,y₁) = (-4,-3).

$(-6,-4)=(\dfrac{-4+x_2}{2},\dfrac{-3+y_2}{2})\\\\\dfrac{-4+x_2}{2}=-6\ \text{and}\ \dfrac{-3+y_2}{2}=-4\\\\-4+x_2=-12\ \text{and}\ -3+y_2=-8\\\\x_2=-12+4\ \text{and}\ y_2=-8+3\\\\x_2=-8\ \text{and}\ y_2=-5$