I don't know if we can find the foci of this ellipse, but we can find the centre and the vertices. First of all, let us state the standard equation of an ellipse.
(If there is a way to solve for the foci of this ellipse, please let me know! I am learning this stuff currently.)

Where

is the centre of the ellipse. Just by looking at your equation right away, we can tell that the centre of the ellipse is:

Now to find the vertices, we must first remember that the vertices of an ellipse are on the major axis.
The major axis in this case is that of the y-axis. In other words,
So we know that b=5 from your equation given. The vertices are 5 away from the centre, so we find that the vertices of your ellipse are:

&

I really hope this helped you! (Partially because I spent a lot of time on this lol)
Sincerely,
~Cam943, Junior Moderator
Answer: B
Step-by-step explanation: the similar paper appears to be 2 times larger then Fransicos since 38/19=2, so I did 14 1/3*2 which equals 28 2/3, so the answer is B
Answer:
hope you can see these, the red graph is problem 3 and the blue graph is problem 5 :)
d = diameter of the copper wire = 8.252 mm
r = radius of the copper wire = d/2 = 8.252 mm /2 = 4.126 mm = 0.004126 m
A = area of cross-section of the copper wire = πr² = (3.14) (0.004126)² = 53.5 x 10⁻⁶
L = length of the copper wire = 2.40 km = 2400 m
ρ = resistivity of copper wire = 1.68 x 10⁻⁸
resistance of copper wire is given as
R = ρL/A
inserting the above values in the formula
R = ( 1.68 x 10⁻⁸)(2400)/(53.5 x 10⁻⁶)
R = 0.753 ohm