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Slav-nsk [51]
2 years ago
12

If x > 0 and y > 0, where is the point (x, y) located?

Mathematics
1 answer:
Scrat [10]2 years ago
8 0
  • Given, x > 0, y > 0.
  • So, the values of x and y are less than 0, that means, they are negative integers.
  • If we divide a Cartesian plane with the x-axis and y-axis, we get four quadrants.
  • 1st Quadrant : (+,+)
  • 2nd Quadrant : (-,+)
  • 3rd Quadrant : (-,-)
  • 4th Quadrant : (+,-)
  • Since the values of x and y are both negative, so (x, y) is located in the <em><u>3rd Quadrant</u></em>.

Hope you could get an idea from here.

Doubt clarification - use comment section

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<u>Step-by-step explanation:</u>

First, you need to complete the square:

y   = -3x² - 5x + 1

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           ↑                     ↓            ↑

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y - 1 - \frac{25}{12} = -3(x + \frac{5}{6})²

y - \frac{12}{12} - \frac{25}{12} = -3(x + \frac{5}{6})²

y  - \frac{37}{12} = -3(x + \frac{5}{6})²

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Now, it is in the form of y = a(x - h)² + k   <em>where (h, k) is the vertex</em>

Vertex = (-\frac{5}{6}, \frac{37}{12})

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