1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oliga [24]
2 years ago
15

Solve each system substitution 6x - 12y=24 And -x - 6y=4

Mathematics
1 answer:
almond37 [142]2 years ago
4 0
6x-12y=24
x=-6y-4
6(-6y-4)-12y=24
-36y-24-12y=24
-48y=48
y=-1
6x-12(-1)=24
6x+12=24
6x=12
x=2

6(2)-12(-1)=24
12+12=24
 24=24 true
and
-(2)-6(-1)=4
-2+ 6=4
4=4 true
You might be interested in
The owner of a used car lot wants to buy many cars at an auction as he can while not spending more than $20000. If he expects th
AleksAgata [21]

Answer:

5

Step-by-step explanation:

Given that:

Total maximum amount that the owner wishes to spend = $20000

Average price of each car = $4000

To find:

How many cars that the owner can expect to buy?

Solution:

Total number of cars that the owner can expect to buy can be found by dividing the total money available with the owner with the average price of each car.

i.e.

\text{Number of cars expected to be bought} = \dfrac{\text{Total money available with the owner}}{\text{Average Price of car}}

We have the following values as given in the question statement:

Total money available = $20000

Average price of car = $4000

Therefore, the answer is:

\text{Number of cars expected to be bought} = \dfrac{20000}{4000} = \bold{5}

The owner can expect to buy 5 number of cars.

7 0
2 years ago
PLEASE HELP IT'S URGENT!!!
Step2247 [10]

Answer:

C. A and C

Both pass by (1,2)

7 0
3 years ago
Natalia bought 8 glitter wands for $50. Determine whether or not each wand purchase below has the same price per wand as glitter
viva [34]

Answer:

Sparkle wands:  NO

Fairy wands:  YES

Glass wands:  NO

Step-by-step explanation:

To find the price per glitter wand, you have to divide the price of the wands by the amount of wands you have.

$50/8 = $6.25

Divide the price of the wands by the amount you get.

Sparkle wands:  $20/4 = $5

Fairy wands:  $37.50/6 = $6.25

Glass wands:  $65/10 = $6.50

The sparkle wands and the glass wands do not have the same price per wand as glitter wands.

The fairy wands have the same price per wand as glitter wands.

8 0
3 years ago
I have one third gallon of juice and one sixth gallon. How many more gallons is need to make three gallons
charle [14.2K]

Answer:

2.5 gallons

Step-by-step explanation:

Make the denominators of the fractions the same and combine them

\frac{1}{3} =\frac{2}{6}

\frac{2}{6} +\frac{1}{6} =\frac{3}{6}

Then simplify the fraction

\frac{3}{6} =\frac{1}{2}

Then subtract how many gallons you have from how many you want

3 -\frac{1}{2} = 2\frac{1}{2}

You will need 2.5 gallons to make 3 gallons

3 0
3 years ago
Answer #1,3,4,5,6,and 7
Fofino [41]
Can you type the answers in plz. I can't see the pic
7 0
3 years ago
Other questions:
  • At haley's bakery over the course of a year she sold 81 birthday cakes for $66 a cake. At the end of the year she determined tha
    12·1 answer
  • What flavor goldfish​
    10·1 answer
  • Which graph represents the function?
    11·1 answer
  • McSaw’s Ice Cream makes muffins that cost $.60 each. Past experience shows that 10% of the muffins will become stale and have to
    5·1 answer
  • Question 20
    9·1 answer
  • To win a trivia game, Nathan must score at least 75 points. Each correct answer is worth 2 1/2 points, and each incorrect answer
    7·1 answer
  • Which is a secant? MH CT CD
    8·1 answer
  • The mathematical model C = 800x + 100,000 represents the cost in dollars a company has in manufacturing x items during a month.
    13·1 answer
  • If Fred made $350 more than Jamie last month and Jamie made twice as much as Karl while together the three of them made $19,230,
    5·1 answer
  • Help me please for 50 points<br> I'll also give brainliest
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!