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marusya05 [52]
3 years ago
9

Sue made a batch of snack mix for the party. She combined 12 ounces of mixed nuts, 20 ounces of cereal, and 8 ounces of pretzels

. What percent of the snack mix are pretzels?
Mathematics
1 answer:
Levart [38]3 years ago
6 0

Answer:

The pretzels are 20% of the total weight of the snack.

Step-by-step explanation:

Total weight 12 + 20 + 8 = 40

So 8 / 40 = 20%

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lubasha [3.4K]

Edit: I have poor vision! My anwser was incorrect

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Step-by-step explanation:

can start by looking at the squares of the graph and do the rise over run

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3 years ago
I really need help please
konstantin123 [22]

Answer:

7 muffins

Step-by-step explanation:

First, you must figure out how many times 9 can go into 88. That gives you 9.8. This tells you that 9 boxes will be filled completely. You then multiply 9 by 9 to figure out how many muffins that will be (81). Lastly, you subtract those (81) from the total muffins to find out how many muffins are left that will be in the small box.

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3 years ago
Simplify 6^9/6^3<br><br> 20 characters :/
Jet001 [13]

Answer:

=46,656

Step-by-step explanation:

=6^9                               =6^3

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5 0
3 years ago
When truckers are on long-haul drives, their driving logs must reflect their average speed. Average speed is the total distance
bekas [8.4K]

a) v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}

The average speed is equal to the ratio between the total distance (d_{tot} and the total time taken (t_{tot}):

v=\frac{d_{tot}}{t_{tot}}

the distance travelled by the trucker in the first 3 hour can be written as the time multiplied by the velocity:

d_1 = (3 h)(60 mph)=180 mi

So the total distance is

d_{tot}=d_1 +d_2 = 180 mi+20 mi=200 mi

The total time is equal to the first 3 hours + the time taken to cover the following 20 miles in the city:

t_{tot}=3 h +t_2

So, the equation can be rewritten as:

v=\frac{d_{tot}}{t_{tot}}=\frac{(3 h)(60 mph)+20 mi}{3 h +t_2}


b) 0.50 h (half a hour)

Since we know the value of the average speed, v=57.14 mph, we can substitute it into the previous equation to find the value of t_2, the time the trucker drove in the city:

v=\frac{200 mi}{3h +t_2}\\3h+t_2 = \frac{200 mi}{v}\\t_2 = \frac{200 mi}{v}-3h=\frac{200 mi}{57.14 mph}-3 h=0.50 h


3 0
3 years ago
Use the guess-and-check method to solve the equation:
Sidana [21]
B x is equal to 3
hope this helps
4 0
3 years ago
Read 2 more answers
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