If cos Theta < 0, which quadrent(s) could the terminal side of Theta lie?
1 answer:
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Slope Intercept Form - y = mx + b
First you need the slope or m which in the first equation is 6 and in the second is 5
Next the y-intercept or b which in the first equation is -4 and in the second is -3
Here is an image of both equation plotted on a graph where the first equation is purple and the second is green
Hope this helps, if you need anything else i will edit it in :)
edit: The to lines intercept at the point (1,2)
Sorry, i wasn't completely sure what you needed i haven't done this in a while. If you still need more, I'll try to help.
In order to make b the subject of this equation, we must isolate it on the left side. We can do this by following these steps:
Subtract b from both sides
Subtract P from both sides
Now, we have isolated b, but it is negative. We can fix this by multiplying both sides of the equation by -1.
Which is your final answer.
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Hope that helped! =)
Subtract b from both sides
Subtract P from both sides
Now, we have isolated b, but it is negative. We can fix this by multiplying both sides of the equation by -1.
Which is your final answer.
Hope that helped! =)