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son4ous [18]
3 years ago
7

The theory of endosymbiosis suggests that chloroplasts and mitochondria were once free-living prokaryotes, that were engulfed by

larger prokaryotic cells. Eventually, this relationship lead to the development of eukaryotic cells with cellular organelles. These organelles included mitochondria, and in some cases, chloroplasts. Which of these is not supported by the endosymbiosis theory concerning organelles? A) contain DNA. B) contain ribosomes. C) are capable of living independently. D) are surrounded by a double membrane.
Biology
2 answers:
hammer [34]3 years ago
7 0
C) are capable of living independently.
Organelles are NOT capable of living in their own. Cells are the smallest units of life.
givi [52]3 years ago
7 0
I think it's C) because organalles are not capable of living independenly. They are in need of the help of other cell material which will help them survive.
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Please help me
Tju [1.3M]
I think the correct answer is c
4 0
3 years ago
Prokaryotes and eukaryotes are similar in all of these aspects except
Leya [2.2K]
Their difference is that Eukaryotes posses nucleus & nuclear bound organelles whereas prokaryotes doesn't!

Hope this helps!
5 0
3 years ago
Read 2 more answers
Which one is it? 8,2,12,6
diamong [38]

Answer:

6

Explanation:

3 0
3 years ago
a race car driver drives one lap around a track that is 500 meters in length. what is the drivers displacement at the end of the
sleet_krkn [62]

Answer:

0 meters

Explanation:

When we talk about displacement, think that the think of it as the measure of the distance between the starting point of the object, from its end point.

Since we are talking about a lap around a track, it would mean that the starting point is also the end point. So if you started and end at the same point, the distance between it would be 0.

5 0
3 years ago
A breeder is trying to decrease the maturation time in a population of sunflowers. In this population, the mean time to flowerin
aalyn [17]

Answer:

The next generation average time to flowering will be 98 days.

Explanation:

Before answering the question, we need to know a few concepts.

  • Artificial selection is the selecting practice of a specific group of organisms in a population -that carry the traits of interest- to be the parents of the following generations.  
  • Parental individuals carrying phenotypic values of interest are selected from the whole population. These parents interbreed, and a new generation is produced.  
  • The selection differential, SD, is the difference between the mean value of the trait in the population (X₀) and the mean value of the parents, (Xs). So,  

SD = Xs - X₀

  • Heritability in the narrow-sense, h², is the genetic component measure to which additive genetic variance contributes. The heritability might be used to determine how the population will respond to the selection done, R.  

h² = R/SD

  • The response to selection (R) refers to the metric value gained or lost from the cross between the selected parents. R can be calculated by multiplying the heritability h², with the selection differential, SD.  

R = h²SD  

R also equals the difference between the new generation phenotypic value (X₁) and the original population phenotypic value (X₀),  

R = X₀ - X₁

-------------------------------------------------------------------------------------------------------------

Now that we know these concepts and how to calculate them, we can solve the proposed problem.

<u>Available data:  </u>

  • trying to decrease the maturation time in a population of sunflowers.
  • the population mean time to flower is 100 days → X₀
  • Chosen parental Plants mean flowering time is 90 days → Xs
  • the narrow-sense heritability for flowering time is 0.2 → h²

According to what we sow previously, we need to find out the value of X₁, which reflects the next generation average time to flowering.

  • We know that R = X₁ - X₀, so we need to clear this formula to calculate X₁

X₁ = R + X₀

We already know that X₀ = 100 days,  

Now we need to calculate R.  

  • R = h²SD

We know that h² = 0.2,  

Now we need to calculate SD

  • SD = Xs - X₀

Xs = 90 days → Parentals media flowering time

X₀ = 100 → Population media flowering time

SD = Xs - X₀  

SD = 90 - 100  

SD = - 10 days

Knowing this, we can calculate R

  • R = h²SD

o h² = 0.2  

o SD = - 10

R = 0.2 x (-10)

R = - 2

  • Finally, once we know the R-value we can calculate the X₁ value

X₁ = R + X₀

X₁ = - 2 + 100

X₁ = 98

6 0
2 years ago
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