The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
$28
Step-by-step explanation:
Time = 4 hours
Charge = $7 / hour
Multiply those two numbers:
4 hour × $7 / hour = $28
Function f(time) = $7 × time
Hopefully this answer helps you :)
Answer:
The answer is x=10
Step-by-step explanation:
5/6x - 10 = 1/3x -5 multiple both sides by 6
5x - 60 = 2x -30 move the terms
5x - 2x = -30 +60
3x = 30 divide by 3
x = 10
Answer:
9m + 16n
Step-by-step explanation:
14m+2n-5m+20m-6n
9m+2n+20n-6n
add like variable
9m + 16n