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3 years ago

PLEASE HELP 10 POINTS

Mathematics

1 answer:

trapecia [35]3 years ago

6 0

Answer:

Angle 1 and Angle 3 are both 38 degrees. Angle 2 is 142 degrees.

Step-by-step explanation:

Angle 1 and 3 are the same size and both supplementary to Angle 4.

180 - 142 = 38 degrees

Angle 2 and Angle 4 are going to be the same size since they are vertical angles so 142 degrees

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3 years ago

10. Which is the equation of a line that is perpendicular to the line represented by y=3/4x-1/2

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2 years ago

What is the answer to 3/x-2 is ≥12

Tju [1.3M]

Answer:

The answer to your question is 0 < x ≤ 3/14

Step-by-step explanation:

Here are the steps to solve it.

First, you need to solve your inequality step-by-step:

3/x −2 ≥ 12

-2x + 3/x = ≥12

Next, find the critical points of the inequality:

2x + 3/x = 12

−2x + 3 = 12x (Multiply both sides by x)

−2x + 3 − 12x = 12x − 12x (Subtract 12x from both sides)

−14x + 3 = 0

−14x + 3 − 3 = 0 − 3 (Subtract 3 from both sides)

−14x = −3

-14x/ -14 = -3/ -14 (Divide both sides by -14)

So, that gives you your answer:

x = 3/14

3 0

3 years ago

Find the measure of the the sides of DEF then classify it by it sides. <br> D(8,-6) E(-1,-3) F(-2,5)

Mama L [17]

Answer:

Part a) The measure of the sides of triangle DEF are

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Part b) Is a scalene triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the coordinates

D(8,-6) E(-1,-3) F(-2,5)

step 1

Find the length side DE

D(8,-6) E(-1,-3)

substitute in the formula

$d=\sqrt{(-3+6)^{2}+(-1-8)^{2}}$

$d=\sqrt{(3)^{2}+(9)^{2}}$

$d_D_E=\sqrt{90}\ units$

step 2

Find the length side EF

E(-1,-3) F(-2,5)

substitute in the formula

$d=\sqrt{(5+3)^{2}+(-2+1)^{2}}$

$d=\sqrt{(8)^{2}+(-1)^{2}}$

$d_E_F=\sqrt{65}\ units$

step 3

Find the length side DF

D(8,-6) F(-2,5)

substitute in the formula

$d=\sqrt{(5+6)^{2}+(-2-8)^{2}}$

$d=\sqrt{(11)^{2}+(-10)^{2}}$

$d_D_F=\sqrt{221}\ units$

step 4

Classify the triangle by the measure of its sides

we have

$d_D_E=\sqrt{90}\ units$

$d_E_F=\sqrt{65}\ units$

$d_D_F=\sqrt{221}\ units$

Is a scalene triangle, because is a triangle in which all three sides have different lengths.

6 0

3 years ago