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Gnesinka [82]
4 years ago
11

It is 20 minutes before 8:00 am in the morning. What time is this?

Mathematics
1 answer:
Masja [62]4 years ago
5 0
It is 7:40am in the morning
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Omar drew a number line that went from -10 to 10 and used it to compare integers. Which statement is true?
Evgen [1.6K]

Answer:

-7 < -3 because -7 is located to the left of -3 on a number line.

Step-by-step explanation:

This is because -7 is on the left of the -3. In negatives -3 is greater than -7. If it was positive then 7 would be greater than 3. So the answer is A. -7 < -3 because -7 is located to the left of -3 on a number line

4 0
4 years ago
To rent a bounce house: At Mike's Bounce Shop costs $30 plus $2 per hour. At Jose's Bounce Rentals, it costs $12 plus $8 per hou
ANEK [815]

Answer: After 3 hours both will have the same cost.

Step-by-step explanation:

Let x = Number of hours and y be the total cost.

Total cost = Initial cost + (cost per hour)(Number of hours)

At Mike's Bounce Shop,

Total cost (y)= 30+2x

At Jose's Bounce Rentals,

Total cost(y) =  12+8x

When both shops have the same cost, then

12+8x=30+2x\\\\\Rightarrow\ 8x-2x=30-12\\\\\Rightarrow\ 6x=18\\\\\Rightarrow\ x=3

Total cost = 12+8(3)=12+24=$36

Hence, After 3 hours both will have the same cost.

3 0
3 years ago
PLS HELP I NEED HELP
Vinvika [58]

Answer:

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3 years ago
The distance from Houston to
marissa [1.9K]

Answer:

distance from Houston to Galveston in  kilometers will be: 80km

Step-by-step explanation:

Given

The distance from Houston to  Galveston is about 50 miles.

i.e.

Kilometers in 1 Mile = 1.6 km

As the distance from Houston to  Galveston is about 50 miles, so

The distance from Houston to Galveston in  kilometers will be:

50(1.6) = 80   ∵ Kilometers in 1 Mile = 1.6 km

Therefore,

The distance from Houston to Galveston in  kilometers will be: 80km

8 0
3 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\\\&#10;&#10;\begin{array}{rllll} &#10;% left side templates&#10;f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}&#10;\\\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}&#10;\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|&#10;\\\\\\&#10;\begin{array}{lllcclll}&#10;f(x)=&3|&1x&+2|&+4\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
3 years ago
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