C(x)=- 0.3x^2+600x
y=ax^2+bx+c
it shows a upside down parabola equation.
to find maximum value we need to find its vertex(h,k)
as this is a standard quadratic equation we need to see parabolis equation too
y=a(x-h)^2+k
if u see this eq^n K would be the maximum value of Y if x=h.
where h,k are vertex of parabola.
h=-b/2a(derived standard formula)
C(x)=- 0.3x^2+600x
y=ax^2+bx+c
a= -0.3 b=600
h=-600/-0.3
h= 2000
put h in place of x to get K
K= -0.3(2000)^2+600(2000)
K= - 1200000+1200000
K=0
u gets k=0
means C(x)=0
600x= -0.3x^2
600= 0.3x
x=6000/3
x= 2000 units
Answer:
Student A says this estimate is reasonable because… Get ... Student A says this estimate is reasonable because the product is negative and about half of 1.5. Student B says you could find the product using a calculator as follows: "Divide −18 by 35, multiply the quotient by 1.43, then round the product
Step-by-step explanation:
calculations with a calculator or computer we need a way of checking that the answers it ... introduce students to this way of thinking and give them practice at estimating simple ... Do they always get the right answer no matter what? Invent a story illustrating a calculator error that you may have made or use the following.
Answer:
4
Step-by-step explanation:
10×4=40
18×4=72
11×4=44
Let x be the number of agents required during peak hours. This value should be 32% more than the given number of agents in the afternoon which is 473.
x = 473 + 0.32(473)
x = 624.36
Since, we cannot have the number of agents in decimal place, we round up the value. Thus, the number of agents required during peak hours is approximately equal to 625.
