Answer:
39.6 cm
Step-by-step explanation:
Applying
s = 2πrθ/360................ Equation 1
Where s = length of an arc or distance traveled by the minutes hand of the clock during the 42 munites, r = length of the minutes hand of the clock, θ = Angle traveled by the minute hand of the clock for every 42 minutes
From the question,
Given: r = 9 cm, θ = 252°
Constant: π = 22/7 = 3.14
Substitute these values into equation 1
s = (2×3.14×9×252)/360
s = 39.564
s = 39.6 cm
Answer:
15.78°
Step-by-step explanation:
Let the angle be x.
From the x, the known sides are the opposite side, O(13) and the adjacent side, A(46)
Therefore, The trigonometric ratio is the tangent ratio.
tan x = O/A
tan x =13/46
x = 15.78°
Answer:28.50
I’m doing a lesson for iready and I had the same question
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
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