Answer:
Two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle. Which congruence theorem can be used to prove that the triangles are congruent? Two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle.
Answer:
i)32C16
ii)1185408
<em><u>Explanation</u></em><em><u>:</u></em>
i)Total number of selected/eligible is 7+9+8+8=32
Total ways of selecting dance committee of 16 is
<em><u>3</u></em><em><u>2</u></em><em><u>C</u></em><em><u>1</u></em><em><u>6</u></em>
ii)Total ways of selecting 3 seniors from 8 is 8C3
and Total ways of selecting 6 juniors from 8 is 8C6
ways of selecting 2 sopho from 9 is 9C2
ways of selecting 5 freshman from 7 is 7C5
now, total way of selection come to be
8C3×8C6×9C2×7C5
=56×28×36×21
=1185408
✌️
Answer:
56 cm squared
Step-by-step explanation:
First things first: Cop one triangle off the rectangle, and attach it to the other one, so the shape looks like a L
Now I can actually solve this:
The left side is 8 cm (because y = 8 cm)
The top is 10 cm
The middle is 6 cm
The inside left is 3 cm
And the very bottom is 2 cm
First, we'll solve for the newly constructed rectangle: 3 x 2. That equals 6.
Next, solve for the longer rectangle: 10 x 5. That's 50.
Now, add the two areas, and we get 56. So the area of the whole thing is 56 cm squared.
(Please keep in mind that I could be wrong, so double check it for me, thanks!)
Answer: The answer I got was A) 2.5
Step-by-step explanation:
Hope this Helps!!!
