true or false the standard error of the sum and the standard error of the average both get smaller as the sample size increases

Georgia ,a florist,charges $10 per flower bundle plus a$15 delivery charge per order what is the slopes

andrew11 [14]

Answer:

The slope is $ 10 per flower bundle.

Explanation:

The slope of a linear function is the ratio of the change in the dependent variable over the change in the independent variable.

In the problem, the independent variable is the number of flower bundles and the dependent variable is the amount charged.

If you call n the number of flower bundles and c(n) the amount charged per order, the amount charged per order is modeled by linear function:

c(n) = 10n + 15

Where, 10 is the amount charged in dolars per flower bundle, and 15 is the delivery charge per order.

Then, for every increment in the number of flower bundles (n) the amount charged will increase in $ 10. That is the slope

slope = $ 10 / flower bundle.

3 0

2 years ago

You are given a bag with 8 green marbles, 6 blue marbles, 14 yellow marbles, and 12 red marbles. Find the theoretical probabilit

AysviL [449]

A) 8/40 = 1/5
b) 12/40 or 6/20
c) 26/40 or 13/20

6 0

2 years ago

There are 15 identical pens in your drawer, nine of which have never been used. On Monday, yourandomly choose 3 pens to take wit

DaniilM [7]

Answer: p = 0.9337

Step-by-step explanation: from the question, we have that

total number of pen (n)= 15

number of pen that has never been used=9

number of pen that has been used = 15 - 9 =6

number of pen choosing on monday = 3

total number of pen choosing on tuesday=3

note that the total number of pen is constant (15) since he returned the pen back .

probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

probability of picking a pen that has been used on tuesday = 6/15 = 2/5

probability of not picking a pen that has not been used on tuesday= 1- 2/5= 3/5

on tuesday, 3 balls were chosen at random and we need to calculate the probability that none of them has never been used .

we know that

probability of ball that none of the 3 pen has never being used on tuesday = 1 - probability that 3 of the pens has been used on tuesday.

to calculate the probability that 3 of the pen has been used on tuesday, we use the binomial probability distribution

p(x=r) = $nCr * p^{r} * q^{n-r}$

n= total number of pens=15

r = number of pen chosen on tuesday = 3

p = probability of picking a pen that has never been used on tuesday = 9/15 = 3/5

q = probability of not picking a pen that has never been used on tuesday = 1-3/5=2/5

by slotting in the parameters, we have that

p(x=3) = $15C3 * (\frac{2}{5})^{3} * (\frac{3}{5})^{12}$

p(x=3) = 455 * $0.4^{3} * 0.6^{12}$

p(x=3) = 455 * 0.064 * 0.002176

p(x=3) = 0.0633

thus probability that 3 of the pens has been used on tuesday. = 0.0633

probability of ball that none of the 3 pen has never being used on tuesday = 1 - 0.0633 = 0.9337

3 0

2 years ago

If u=6 feet, v=7 feet, w=4 feet, x=6 feet, y=12, and z=3 feet, what is the area of this object?

eimsori [14]

Answer:

D. 62 square feet

Step-by-step explanation:

uz + wx + (v+z)(y-u-w)

6*3 + 4*6 + (7+3)(12-6-4)

18 + 24 + 20 = 62

7 0

2 years ago

How do you solve System of Equations?

Katarina [22]

The addition method of solving systems of equations is also called the method of elimination. This method is similar to the method you probably learned for solving simple equations.

If you had the equation "x + 6 = 11", you would write "–6" under either side of the equation, and then you'd "add down" to get "x = 5" as the solution.

x + 6 = 11
–6 –6
x = 5

You'll do something similar with the addition method.

Solve the following system using addition.2x + y = 9
3x – y = 16Note that, if I add down, the y's will cancel out. So I'll draw an "equals" bar under the system, and add down:2x + y = 9
3x – y = 16
5x = 25Now I can divide through to solve for x = 5, and then back-solve, using either of the original equations, to find the value of y. The first equation has smaller numbers, so I'll back-solve in that one:2(5) + y = 9
 10 + y = 9
 y = –1Then the solution is (x, y) = (5, –1).

It doesn't matter which equation you use for the backsolving; you'll get the same answer either way. If I'd used the second equation, I'd have gotten:

3(5) – y = 16
 15 – y = 16
 –y = 1
 y = –1

...which is the same result as before.

Solve the following system using addition.x – 2y = –9
x + 3y = 16Note that the x-terms would cancel out if only they'd had opposite signs. I can create this cancellation by multiplying either one of the equations by –1, and then adding down as usual. It doesn't matter which equation I choose, as long as I am careful to multiply the –1 through the entire equation. (That means both sides of the "equals" sign!)I'll multiply the second equation.The "–1R2" notation over the arrow indicates that I multiplied row 2 by –1. Now I can solve the equation "–5y = –25" to get y = 5. Back-solving in the first equation, I get:x – 2(5) = –9
x – 10 = –9
x = 1Then the solution is (x, y) = (1, 5).

A very common temptation is to write the solution in the form "(first number I found, second number I found)". Sometimes, though, as in this case, you find the y-value first and then the x-value second, and of course in points the x-value comes first. So just be careful to write the coordinates for your solutions correctly. Copyright © Elizabeth Stapel 2003-2011 All Rights Reserved

Solve the following system using addition.2x – y = 9
3x + 4y = –14Nothing cancels here, but I can multiply to create a cancellation. I can multiply the first equation by 4, and this will set up the y-terms to cancel.Solving this, I get that x = 2. I'll use the first equation for backsolving, because the coefficients are smaller.2(2) – y = 9
4 – y = 9
–y = 5
y = –5The solution is (x, y) = (2, –5). Solve the following system using addition. 
 4x – 3y = 25
–3x + 8y = 10Hmm... nothing cancels. But I can multiply to create a cancellation. In this case, neither variable is the obvious choice for cancellation. I can multiply to convert the x-terms to 12x's or the y-terms to 24y's. Since I'm lazy and 12 is smaller than 24, I'll multiply to cancel the x-terms. (I would get the same answer in the end if I set up the y-terms to cancel. It's not that how I'm doing it is "the right way"; it was just my choice. You could make a different choice, and that would be just as correct.)I will multiply the first row by 3 and the second row by 4; then I'll add down and solve.
Solving, I get that y = 5. Neither equation looks particularly better than the other for back-solving, so I'll flip a coin and use the first equation.4x – 3(5) = 25
4x – 15 = 25
4x = 40
x = 10Remembering to put the x-coordinate first in the solution, I get:(x, y) = (10, 5)

Usually when you are solving "by addition", you will need to create the cancellation. Warning: The most common mistake is to forget to multiply all the way through the equation, multiplying on both sides of the "equals" sign. Be careful of this.

Solve the following using addition.12x – 13y = 2
–6x + 6.5y = –2I think I'll multiply the second equation by 2; this will at least get rid of the decimal place.Oops! This result isn't true! So this is an inconsistent system (two parallel lines) with no solution (with no intersection point).no solution Solve the following using addition.12x – 3y = 6
4x – y = 2I think it'll be simplest to cancel off the y-terms, so I'll multiply the second row by –3.Well, yes, but...? I already knew that zero equals zero. So this is a dependent system, and, solving for "y =", the solution is:y = 4x – 2

(Your text may format the answer as "(s, 4s – 2)", or something like that.)

6 0

3 years ago

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