<span>Defective rate can be expected
to keep an eye on a Poisson distribution. Mean is equal to 800(0.02) = 16,
Variance is 16, and so standard deviation is 4.
X = 800(0.04) = 32, Using normal approximation of the Poisson distribution Z1 =
(32-16)/4 = 4.
P(greater than 4%) = P(Z>4) = 1 – 0.999968 = 0.000032, which implies that
having such a defective rate is extremely unlikely.</span>
<span>If the defective rate in the
random sample is 4 percent then it is very likely that the assembly line
produces more than 2% defective rate now.</span>
Answer:
Sin 5/13
Cos 12/13
Tan 5/12
Csc 13/5
Sec 13/12
Cot 12/5
Step-by-step explanation:
Answer:

Step-by-step explanation:
The equation
represents the discriminant of a quadratic. It is the part taken from under the radical in the quadratic formula.
For any quadratic:
- If the discriminant is positive, or greater than 0, the quadratic has two solutions
- If the discriminant is equal to 0, the quadratic has one distinct real solution (the solution is repeated).
- If the discriminant is negative, or less than 0, the quadratic has zero solutions
In the graph, we see that the equation intersects the x-axis at two distinct points. Therefore, the quadratic has two solutions and the discriminant must be positive. Thus, we have
.
we have 630 one-inch unit cubes and we want to completely fill the rectangular box (unknown dimensions).
If all the cubes are fitted tightly inside rectangular box without living any space, then box volume would be equal to cubes volume.
There are 630 one-inch unit cubes, so volume of cubes = 630 cubic inches.
Now the volume of rectangular box would also be 630 cubic inches.
We know the formula for volume of rectangular box = length ×
width × height.
So we need to find any three positive integers whose product is 630.
Out of all given choices, only option A satisfies the condition of factors of 630.
Hence, option A i.e. (7 in x 9 in x 10 in) is the final answer.
Answer:
The volume of can A is half the volume of can B.
Step-by-step explanation:
Given
Can A and Can B
Required
The true statement
For Can A, we have:


The volume is:

This gives:



For Can B, we have:


The volume is:

This gives:



So, we have:


By comparison, (d) is correct