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bogdanovich [222]
3 years ago
9

Isaac wrote the integers from 1 through 104, inclusive. How many digits did he write?

Mathematics
1 answer:
Lilit [14]3 years ago
6 0

We know that Isaac wrote the integers from 1 to 104, and we need to determine how many digits did he write

Let's look at single digit, double digit and triple digit numbers separately:

Single Digit Numbers' Range: 1-9

Total Single Digit Numbers = Ending Number - Beginning Number + 1

⇒ Total Single Digit Numbers = 9 - 1 + 1 = 9

Number of digits written in single digit numbers = 9 × 1 = 9 ......... (i)

Double Digit Numbers' Range: 10-99

Total Double Digit Numbers = Ending Number - Beginning Number + 1

⇒ Total Double Digit Numbers = 99 - 10 + 1 = 90

Number of digits written in double digit numbers = 90 × 2 = 180 ....... (ii)

Triple Digit Numbers' Range: 100-104

Total Triple Digit Numbers = Ending Number - Beginning Number + 1

⇒ Total Triple Digit Numbers = 104 - 100 + 1 = 5

Number of digits written in triple digit numbers = 5 × 3 = 15 .......... (iii)

Adding (i), (ii) and (iii)

Total number of digits written from 1-104 = 9 + 180 + 15

⇒ Total number of digits written from 1-104 = 204

Hence, while writing the integers from 1-104, we use 204 digits.

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Please help :) I have no clue & math isn’t my strong subject.
melisa1 [442]

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

Solution:

Given line y=\frac{4}{7} x+4.

Slope of this line, m_1 = \frac{4}{7}

$\text{Slope of perpendicular line} = \frac{-1}{\text{Slope of the given line} }

                                   $m_2=\frac{-1}{m_1}

                                          $=\frac{-1}{\frac{4}{7} }

Slope of perpendicular line, m_2=\frac{-7}{4}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

y-y_1=m(x-x_1)

$y-(-7)=\frac{-7}{4} (x-5)

$y+7=\frac{-7}{4} x+\frac{35}{4}

Subtract 7 from both sides, we get

$y=\frac{-7}{4} x+\frac{7}{4}

Equation of a line that is perpendicular to given line is y=\frac{-7}{4} x+\frac{7}{4}.

To find the parallel line:

Slopes of parallel lines are equal.

m_1=m_3

$m_3=\frac{4}{7}

Passes through the point (–7, 5). Here x_1=-7, y_1=5.

Point-slope formula:

$y-(-7)=\frac{4}{7} (x-5)

$y+7=\frac{4}{7} x-\frac{20}{7}

Subtract 7 from both sides,

$y=\frac{4}{7} x-\frac{69}{7}

Equation of a line that is parallel to given line is y=\frac{4}{7} x-\frac{69}{7}.

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Step-by-step explanation:

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