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3 years ago

Seventy-two people are enrolled in the Bible learners department. If 37.5% are absent, how many people are absent?

Mathematics

1 answer:

Molodets [167]3 years ago

3 0

192 people are absent

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If the circumference of a certain circle of radius r is greater than the area of the enclosed circular region then

shepuryov [24]

Your answer is E because that isn't possible.

4 0

3 years ago

What is x2 – 6 = 16x + 30 rewritten in standard form, then factored?

kaheart [24]

Answer:

Step-by-step explanation:

$x^2-6=16x+30\\\mathrm{Subtract\:}30\mathrm{\:from\:both\:sides}\\x^2-6-30=16x+30-30\\Simplify\\x^2-36=16x\\\mathrm{Subtract\:}16x\mathrm{\:from\:both\:sides}\\x^2-36-16x=16x-16x\\\Simplify\\x^2-16x-36=0$

5 0

3 years ago

Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan

SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola. The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

x = 20

When x = 20, y = 60. So the garden should be 20 ft by 60 ft.

4 0

2 years ago

A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning

zvonat [6]

Answer: $46x^2+73x+15$

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

$A=lw$

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are $(6x+7)$ by $(8x+5)$ , its area is:

$A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35$

As they are planning that the dimensions of the mural be $(x+4)$ by $(2x+5)$ , its area is:

$A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20$

Then the area of the remaining wall after the mural has been painted is:

$A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15$

8 0

3 years ago

if 16 men can finish to contruct a bulding in 40 days how manny more men are needed to finish the contruction in 32 days

Digiron [165]

Answer:

20 mens are needed to contruct a building in 32 days.

5 0

2 years ago