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pantera1 [17]
3 years ago
6

In what direction do seismic waves carry the energy of an earthquake?

Physics
2 answers:
irinina [24]3 years ago
8 0
Seismic waves carry energy from an earthquake away from the focus, through earth's interior and across the surface.
Oxana [17]3 years ago
3 0
<h3><u>Answer;</u></h3>

<em>Away from the focus</em>

Seismic waves carry energy from an earthquake <em><u>away from the focus</u></em>, through earth's interior and across the surface.

<h3><u>Explanation</u>;</h3>
  • <em><u>When an earthquake occurs energy is produced and is transmitted or released in form of a seismic waves.</u></em> Seismic waves are types of waves which results from an earthquake,<em><u> they are vibrations that move through the earth carrying energy</u></em> that has been released when an earthquake occurs.
  • The <u><em>focus is the point at which a rock that is under stress breaks and triggers and earthquake</em></u>. Seismic waves carry the energy released during an earthquake<em><u> away from the focus</u></em> through the earth in all directions.
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Answer:

x=31.09m

Explanation:

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The momentum of flatcar and the momentum of the worker so

The velocity of the worker is:

m_{f}*v_{f}=m_{w}*v_{w}\\\\v_{f}=\frac{m_{f}*v_{f}}{m_{w}}\\v_{f}=\frac{61kg*3.0\frac{m}{s}}{250kg}\\v_{f}=0.732\frac{m}{s}

The total motion has a total velocity and is

Vt=v_{w}+v_{f}\\Vt=0.732\frac{m}{s}+3.0\frac{m}{s}\\Vt=3.732\frac{m}{s}

The time the worker take walking is

t=\frac{x}{v_{w}}\\t=\frac{25m}{3\frac{m}{s}}=8.33s

Now the total time and the total velocity determinate the motion of tha flatcar how far has moved

x=t*Vt\\x=8.33s*3.732\frac{m}{s} \\x=31.09m

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Answer:

Explanation:

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Pachacha [2.7K]

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The work done by a particle from x = 0 to x = 2 m is 20 J.

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