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pantera1 [17]
3 years ago
6

In what direction do seismic waves carry the energy of an earthquake?

Physics
2 answers:
irinina [24]3 years ago
8 0
Seismic waves carry energy from an earthquake away from the focus, through earth's interior and across the surface.
Oxana [17]3 years ago
3 0
<h3><u>Answer;</u></h3>

<em>Away from the focus</em>

Seismic waves carry energy from an earthquake <em><u>away from the focus</u></em>, through earth's interior and across the surface.

<h3><u>Explanation</u>;</h3>
  • <em><u>When an earthquake occurs energy is produced and is transmitted or released in form of a seismic waves.</u></em> Seismic waves are types of waves which results from an earthquake,<em><u> they are vibrations that move through the earth carrying energy</u></em> that has been released when an earthquake occurs.
  • The <u><em>focus is the point at which a rock that is under stress breaks and triggers and earthquake</em></u>. Seismic waves carry the energy released during an earthquake<em><u> away from the focus</u></em> through the earth in all directions.
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Answer:

2.1844 m/s

Explanation:

The principle of conservation of momentum can be applied here.

when two objects interact, the total momentum remains the same  provided no external forces are acting.

Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\

assume the bullet goes to right side and the gravitational acceleration =10 ms^{-2}

so now the weight of the rifle=\frac{25}{10}  

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\\\0=(12.70*10^{-3}) *430ms^{-1} +(\frac{25}{10} )*v_{rifle} \\v_{rifle} =-2.1844ms^{-1}

this is a negative velocity to the right side. that means the rifle recoils to the left side

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3 years ago
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Answer:

Frequency is 213.04\ s^{-1}.

Explanation:

Distance between source 1 from the receiver , S_1 =\sqrt{10^2+22^2}=24.17\ m.

Distance between source 2 from the receiver , S_2=\sqrt{5^2+22^2}=22.56\ m.

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We know, for constructive interference path difference should be integral multiple of wavelength .  

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