When three identical bulbs of 60W,200V rating are connected in series at a 200V supply the power drawn by them will be?
1 answer:
Answer:
P = 180 [w]
Explanation:
To solve this problem we must use ohm's law, which is defined by the following formula.
V = I*R & P = V*I
where:
V = voltage = 200[volts]
I = current [amp]
R = resistance [ohm]
P = power [watts]
Since the bulbs are connected in series, the powers should be summed
P = 60 + 60 + 60
P = 180 [watts]
Now we can calculate the current
I = 180/200
I = 0.9[amp]
Attached is an image where we see the three bulbs connected in series, in the circuit we see that the current is the same for all the elements connected to the circuit.
And the power is defined by P = V*I
we know that the voltage is equal to 200[V], therefore
P = 200*0.9
P = 180 [w]
You might be interested in
Answer:
Explanation:
We can assume this problem as two concentric spherical metals with opposite charges.
We have also to take into account the formulas for the electric field and the capacitance. Hence we have
Where k is the Coulomb's constant. Furthermore, by taking into account the expression for the potential and by integrating
Hence, the capacitance is
but R1=a and R2=b
HOPE THIS HELPS!!
The formula for resonant frequency is:
Given information:
Plug in the given values to find one value of capacitance:
Plug in the given values to find the other value of capacitance:
This gives a range of 2.429 nF to 26.45 nF.
With significant figures taken into account, the range of capacitance is 2.43 nF to 30 nF.