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forsale [732]
4 years ago
7

Can somebody help me with this

Physics
1 answer:
Ivanshal [37]4 years ago
6 0

this is simple the word your looking for is 8 letters long and the definition is key to the answer


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The correct answer is A:) hope it helps :0
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The point is at the edge of the disk and the component bodies are:
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a. A uniform disk of radius and mass .

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Natural selection is the mechanism that?
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Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
Andre45 [30]

Answer:

5501 kg/m^3

Explanation:

The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

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M is the Earth's mass

R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

The Earth's volume is (approximating the Earth to a perfect sphere)

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3

So, the average density of the Earth is

\rho = \frac{M}{V}=\frac{5.98\cdot 10^{24} kg}{1.087\cdot 10^{21} m^3}=5501 kg/m^3

4 0
4 years ago
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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
zloy xaker [14]
Meter and second is the correct answer.
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3 years ago
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