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rjkz [21]
3 years ago
8

Need help on these questions

Physics
1 answer:
Eddi Din [679]3 years ago
6 0
1. V= 110
I= 11
R=10

2. V= 110
I= 5.5
R= 20

3. V= 100
I= 5
R= 20

4. V= 500
I= 5
R= 100

To show work plug in those numbers to V=IR
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Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward he
Harman [31]

Answer:

A

Explanation:

• Nina experiences a force equal to f.

5 0
3 years ago
1. How much heat is required to raise the temperature of 57.8kg of silver from 17.0°C to
Y_Kistochka [10]
Answer: unknown so the second one
I hope this helps you with your stuff
7 0
2 years ago
The Old Faithful geyser found in Yellowstone Park is an example of _____.
katen-ka-za [31]

Answer:

cone geyser

Explanation:

The Old Faithful geyser is the oldest discovered geyser in the Yellowstone national park. The eruptions of the geyser are particularly predictable. It is a cone type geyser.

Cone geysers generally have a spout through which the water ejects out. When super heated water in the tube then the water starts to boil and form bubbles of steam, after this process the eruption takes place.

5 0
3 years ago
The 1st Law of Thermodynamics is a statement about (A) Temperatures scales (B) Whether a process can proceed in a specific manne
weqwewe [10]

Answer:

Energy conservation.

Explanation:

The 1st Law of Thermodynamics is a statement about energy conservation. It states that \Delta U=Q-W, which means that if we <u>substract the work W done</u> by the system to the <u>heat Q given</u> to the system we get the <u>change in the internal energy</u> \Delta U, so any excess in energy given to the system appears as internal energy, stating that energy is conserved.

3 0
3 years ago
Please help. I don’t understand this
skad [1K]

The short answer is that the displacement is equal tothe area under the curve in the velocity-time graph. The region under the curve in the first 4.0 s is a triangle with height 10.0 m/s and length 4.0 s, so its area - and hence the displacement - is

1/2 • (10.0 m/s) • (4.0 s) = 20.00 m

Another way to derive this: since velocity is linear over the first 4.0 s, that means acceleration is constant. Recall that average velocity is defined as

<em>v</em> (ave) = ∆<em>x</em> / ∆<em>t</em>

and under constant acceleration,

<em>v</em> (ave) = (<em>v</em> (final) + <em>v</em> (initial)) / 2

According to the plot, with ∆<em>t</em> = 4.0 s, we have <em>v</em> (initial) = 0 and <em>v</em> (final) = 10.0 m/s, so

∆<em>x</em> / (4.0 s) = (10.0 m/s) / 2

∆<em>x</em> = ((4.0 s) • (10.0 m/s)) / 2

∆<em>x</em> = 20.00 m

5 0
2 years ago
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