The largest transition metal is copernicium with 112 protons.
Answer:
The magnitude of the net force is √2F.
Explanation:
Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:
Then, it means that the net force acting on the test charge has a magnitude of √2F.
<em>Given that:</em>
mass of the ball (m) = 0.5 Kg ,
ball strikes the wall (v₁) = 5 m/s ,
rebounds in opposite direction (v₂) = 2 m/s,
time duration (t) = 0.01 s,
<em> Determine the force (F) = ?</em>
We know that from Newton's II law,
<em>F = m. a</em> Newtons
(velocity acting in opposite direction, so <em>a = ( (v₁ + v₂)/t</em>
= m × (v₁ + v₂)/t
= 0.5 × (5 + 2)/0.01
= 350 N
<em>The force acting up on the ball is 350 N</em>
Direct variation involves ration and proportions, so
you need to set up the proportion:
<span>11 / 75 = x / 65
Cross multiplying:
75x = 11*65
x = (11*65)/75
Solving, we get x = 9.533, </span>
<span>which rounds off to 9.5
Therefore, the spring will stretch up to 9.5 inches with 65 attached.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.
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Answer:
Explanation:
The experimenter is rotating on his stool with angular velocity ω ( suppose )
His moment of inertia is I say
We are applying no torque from outside . therefore , the angular momentum will remain the same
Thus angular momentum L = I ω = constant
Thus we can say I₁ ω₁ = I₂ω₂ = constant
here I₁ is the initial moment of inertia and ω₁ is the initial angular velocity
Similarly I₂ is the final moment of inertia and ω₂ is the final angular velocity
When a been bag is dropped on his lap , his moment of inertia increases due to increase in mass
In the above equation, when moment of inertia increases , the angular velocity decreases . So its motion of rotation will decrease .
