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vaieri [72.5K]
3 years ago
10

Tensile strength tests were performed on two different grades of aluminum spars used in manufacturing the wing of a commercial t

ransport aircraft. From past experience with the spar manufacturing process and the testing procedure, the standard deviations of tensile strengths are assumed to be known. The data obtained are as follows:
n_1 = 10
x_1 = 87.6
σ_1 = 1
n_2 = 12
x^2 = 74.5
σ_2 = 1.5.

Required:
If μ _1 and μ _2 denote the true mean tensile strengths for the two grades of spars. Construct a 90 percentage confidence interval on the difference in mean strength.
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Answer:

(12.141, 14.059)

Step-by-step explanation:

Explanation is provided in the attached document.

Download docx
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If you deposit `\$300` in an account and it grows by `6\%` each year, how much money will be in your account after `1` year?
igomit [66]

Answer:

$318

Step-by-step explanation:

6% x 300 = 18

300 + 18 = 318

5 0
2 years ago
Help please! Thanks
SSSSS [86.1K]

Answer:

E. 0

Step-by-step explanation:

There isn't any guarantee that there are <em>any </em>people that have their birthdays in the same month based on what you're given, so your answer would be 0.

8 0
3 years ago
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
A jar of natural peanut butter normally cost $4.00. Today its on sale for $3.60. What is the percentage of the discount
mafiozo [28]

Answer:

Ambitious

Answer

Find out the what is the percentage of this discount .

To prove

Formula

Discount = Marked price - selling price

As given

a jar of natural peanut butter normally costs $4.00 .

it's on sale for $3.60 .

thus

Marked price = $4.00

selling price = $3.60

put in the above formula

Discount = 4.00 - 3.60

              = 0.4

Formula

put the value

Discount percentage = 10%

Option (a) is correct .

Hence proved

8 0
3 years ago
Write an equation of a parabola that opens to the left, has a vertex at the origin, and a focus at (–4, 0).
8_murik_8 [283]

Answer:

y^{2}=-16x

Step-by-step explanation:

we know that

The standard equation of a horizontal parabola is equal to  

(y-k)^{2}=4p(x-h)

where

(h,k) is the vertex

(h+p,k) is the focus

In this problem we have

(h,k)=(0,0) ----> vertex at origin

(h+p,k)=(-4,0)

so

h+p=-4

p=-4

substitute the values

(y-0)^{2}=4(-4)(x-0)

y^{2}=-16x

8 0
3 years ago
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