Please help me :) Thanks!

Mathematics

2 answers:

ohaa [14]3 years ago

7 0

The minimum value for y in the equation y = x² + 12x + 5 is (-6,-31). Here's how I figured it out:

Step 1: Figure out if the parabola is going up or down. If "a" is positive, the parabola will go up. If "a" is negative, the parabola will go down. In your case...

a = 1
Positive
Up
____________________________________________________________

Step 2: Find the Axis of Symmetry.

Formula: -b -12 -12
--------- = ------------ = ------------- = -6
2a 2(1) 2

The axis of symmetry is x = -6.
____________________________________________________________

Step 3: Plug in the value you found for the axis of symmetry for x into your original equation.

f(-6) = -6² + 12(-6) + 5
f(-6) = 36 - 72 + 5
f(-6) = -36 + 5
f(-6) = -31

The minimum gets written as an ordered pair: (-6,-31).
⊕ The axis of symmetry is the first number in the coordinate pair.
⊕ The answer that you get to step 3 is the second number in the pair.
____________________________________________________________

I hope that my answer helps you! This is the method that I use to solve these types of problems, but there are also other methods.

Oksanka [162]3 years ago

3 0

X^2+12x+5 = (x+6)^2 -31,

So the minimum value is y = -31. Dunno if -31 or you have to type =-31, I guess just '-31'?

With derivatives:

y' = 2x+12=0, x = -6, then y(-6) = 36-72+5 = -36+5 =-31

Just to be sure!!!! lol

You might be interested in

In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t

Basile [38]

So, since averages are defined as:

$\frac{\sum_{k=1}^{P} P_k}{P}=70$

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

$\frac{\sum_{k=1}^{N} N_k}{N}=70$