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3 years ago

Jorge’s printer can print 24 pages in 15 minutes. How many pages can it print in 3/4 hour? In 1 hour?

Mathematics

1 answer:

Art [367]3 years ago

7 0

Jorge's printer can print 72 pages in 3/4 hours and 96 pages in 1 hour.

Step-by-step explanation:

Given,

Pages printed in 15 minutes = 24 pages

15 minutes = $\frac{15}{60} = \frac{1}{4}\ hour$

Therefore;

$\frac{1}{4}\ hour = 24\ pages$

Multiplying both sides by 4

$4*\frac{1}{4}=24*4\\1\ hour = 96\ pages$

In 3/4 hours

$\frac{3}{4}\ hour = 96*\frac{3}{4}\\\\\frac{3}{4}\ hour = 72\ pages$

Jorge's printer can print 72 pages in 3/4 hours and 96 pages in 1 hour.

Keywords: fraction, multiplication

Learn more about fractions at:

#LearnwithBrainly

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Pls help and answer what Y=

coldgirl [10]

Answer:

0.0 hold on

Step-by-step explanation:

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2 years ago

Which inequality correctly compares Two-fifths, Six-sevenths, Five-eighths, and 1?

Ronch [10]

Answer:

2/5 < 5/8 < 6/7 < 1

OR

1 > 6/7 > 5/8 > 2/5

Step-by-step explanation:

It is required to compare Two-fifths, Six-sevenths, Five-eighths, and 1

Two-fifths = 2/5

Six-sevenths = 6/7

Five-eighths = 5/8

So, the given numbers are: 2/5, 6/7, 5/8, and 1

We need to make the numbers in order from the least to the greatest or from the greatest to the least

The easy method is convert the rational numbers to decimal numbers

So,

2/5 = 0.4

6/7 ≈ 0.857

5/8 = 0.625

1 = 1

So, the numbers form the least to the greatest are:

0.4 , 0.625 , 0.857 , 1

So,

2/5 , 5/8 , 6/7 , 1

The inequality correctly compares the numbers are:

2/5 < 5/8 < 6/7 < 1

Or can be written from the greatest to the least as:

1 > 6/7 > 5/8 > 2/5

6 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Steven wants to increase the number of books he reads per year. He currently reads 2 books a year. He wants to triple the number

Sladkaya [172]

Answer:

$B=2\times 3^n$

Step-by-step explanation:

Exponential Growing

Steven currently reads 2 books a year. He wants to triple the number of books read per year. The first year he should read

$2*3 = 6\ books$

By the second year, he should read

$2*3^2 = 18\ books$

By the third year, he should read

$2*3^3 = 54\ books$

We can clearly see there is a geometric progression of the number of books he should read for the year n. The general formula is, being B the number of books read at the year n

$\boxed{B=2\times 3^n}$

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2 years ago

I REALLY NEED HELP! PLEASE HELP ME!!

kirill [66]

Answer:

5:3

Step-by-step explanation:

a burger cost 10 and a hot dog cost 6 so the ratio is literally 10:6 if u want a simplified answer divide both numbers by 2

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2 years ago

Read 2 more answers