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tatuchka [14]
3 years ago
11

Determine whether the triangle with the given side lengths is acute, right, obtuse, or not a triangle 6, 12, 19

Mathematics
2 answers:
anzhelika [568]3 years ago
5 0
The answer is acute , (a)
tekilochka [14]3 years ago
3 0
The answer is A) acute
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The cost of a long-distance telephone call is given by the function
zalisa [80]
The slope would represent the cost per minute, since m is the length of the call in minutes. Logically, D) Cost per minute, is the only one that would work. The connection cost would be just added in, and you wouldn't multiply the cost of having a phone line by how many minutes you're on the phone. The length of the call is already there, it's m, so that wouldn't work either. Therefore, D, cost per minute, is the logical answer. The slope in the equation represents D, cost per minute.
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3 years ago
Draw triangle XYZ with vertices X (-3, 2), Y (4, -2) and Z (-3, -2) on the coordinate plane. Then find the area of the triangle
dmitriy555 [2]

Answer:

14 square units

Step-by-step explanation:

If you graph the points your triangle's height will be 4, and base would be 7.

<em>A = 1/2bh     4</em> x 7 = 28, 28 x 1/2 = 14.

Hope this helps :D

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3 years ago
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There are between 24 and 40 students in the class
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Answer:

33 Students

Step-by-step explanation:

4+7=11 so the number of students in the class must be a multiple of 11. The only multiple of 11 between 24 and 40 is 33.

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3 years ago
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Find the value of "x" in the following : (3^(2x-1) - 5) /2 = 11<br>​
valentina_108 [34]
I’m pretty sure the answer is x=2
6 0
3 years ago
What are the zeros of the quadratic function?<br> y = x^2 - 2x - 15
Pie

Answer:

x=\frac{1+\sqrt{31}}{2},\:x=\frac{1-\sqrt{31}}{2}

Step-by-step explanation:

-> 0=2x^2-2x-15

-zeros means the solution aka x intercept, meaning y=0

x_{1,\:2}=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:2\left(-15\right)}}{2\cdot \:2}

=> according to quadratic formula

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

where ax^2+bx+c=0

=> x_{1,\:2}=\frac{-\left(-2\right)\pm \:2\sqrt{31}}{2\cdot \:2}

simplify

x_1=\frac{-\left(-2\right)+2\sqrt{31}}{2\cdot \:2},\:x_2=\frac{-\left(-2\right)-2\sqrt{31}}{2\cdot \:2}

x=\frac{1+\sqrt{31}}{2},\:x=\frac{1-\sqrt{31}}{2}

Cannot simplify farther

3 0
2 years ago
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