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Brrunno [24]
3 years ago
6

How many grams of Na2CO3 would be needed to prepare 500mL of a 4.00M solution of Na2CO3?

Chemistry
1 answer:
Alexxandr [17]3 years ago
4 0

212 g of sodium carbonate (Na₂CO₃)

Explanation:

We find the number of moles of sodium carbonate (Na₂CO₃) using the following formula:

molar concentration = number of moles / volume (L)

number of moles = molar concentration × volume (L)

number of moles of Na₂CO₃ = 4 × 0.5

number of moles of Na₂CO₃ = 2 moles

Now we calculate the mass of sodium carbonate (Na₂CO₃):

number of moles = mass / molar weight

mass =  number of moles × molar weight

mass of Na₂CO₃ = 2 × 106

mass of Na₂CO₃ = 212 g

Learn more about:

molar concentration

brainly.com/question/14109627

#learnwithBrainly

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