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3 years ago

Why is scientific notation useful?

Chemistry

2 answers:

BlackZzzverrR [31]3 years ago

8 0

It condenses very long strings of numbers while retaining the general accuracy of the figure.

Dmitry [639]3 years ago

5 0

Scientific notation comes in handy because it lets us take very big or very small numbers, get rid of all the zeroes, and write them in a very compact and very simple way that's much easier to use. Also, big numbers aren't just a pain to deal with because of all the digits but they're also hard to quickly evaluate and compare with other numbers.

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What is the relationship between the reactant and yield

solong [7]

Yield is the measured amount of a product obtained from a reaction.

Hope that's helpful

7 0

3 years ago

What occurs in electroplating?

mixas84 [53]

I think it’s the first one. Electroplating means you put on a layer of metal on something.

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3 years ago

Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe

jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

$n=\frac{m}{M_m}$

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

$n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol$

Now we can find the pressure of the gas by using the ideal gas law:

$pV=nRT$

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

$p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm$

8 0

4 years ago

List the factor on which Ka of a weak acid depends

lakkis [162]

I don’t know this, so I did research, so here! This is from a website called “Quora”, btw!
If you need more information, just go to this app by copying and pasting your question on the G o o g l e Search bar!

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3 years ago

Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.

maria [59]

The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%

5 0

3 years ago