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Aliun [14]
3 years ago
14

Why is scientific notation useful?

Chemistry
2 answers:
BlackZzzverrR [31]3 years ago
8 0
It condenses very long strings of numbers while retaining the general accuracy of the figure.
Dmitry [639]3 years ago
5 0

Scientific notation comes in handy because it lets us take very big or very small numbers, get rid of all the zeroes,  and write them in a very compact and very simple way that's much easier to use. Also, big numbers aren't just a pain to deal with because of all the digits but they're also hard to quickly evaluate and compare with other numbers.

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What is the relationship between the reactant and yield
solong [7]
Yield is the measured amount of a product obtained from a reaction.

Hope that's helpful
7 0
3 years ago
What occurs in electroplating?
mixas84 [53]
I think it’s the first one. Electroplating means you put on a layer of metal on something.
5 0
3 years ago
Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe
jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

n=\frac{m}{M_m}

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol

Now we can find the pressure of the gas by using the ideal gas law:

pV=nRT

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm

8 0
4 years ago
List the factor on which Ka of a weak acid depends​
lakkis [162]
I don’t know this, so I did research, so here! This is from a website called “Quora”, btw!
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8 0
3 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
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