Why is scientific notation useful?

Chemistry

2 answers:

BlackZzzverrR [31]3 years ago

8 0

It condenses very long strings of numbers while retaining the general accuracy of the figure.

Dmitry [639]3 years ago

5 0

Scientific notation comes in handy because it lets us take very big or very small numbers, get rid of all the zeroes, and write them in a very compact and very simple way that's much easier to use. Also, big numbers aren't just a pain to deal with because of all the digits but they're also hard to quickly evaluate and compare with other numbers.

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Calculate the number of grams of carbon dioxide produced from 6 moles of oxygen gas. List only the number of grams of carbon dio

faust18 [17]

Answer:

g CO2(g) = 264.06 g

Explanation:

C(s) + O2(g) → CO2(g)

∴ moles O2(g) = 6 mol

∴ mm CO2 = 44.01 g/mol

⇒ mol CO2(g) = ( 6 mol O2(g) )×( mol CO2(g) / mol O2(g) ) = 6 mol CO2(g)

⇒ mass CO2(g) = ( 6 mol CO2(g) )×( 44.01 g/mol ) = 264.06 g CO2(g)

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3 years ago

Express 749 000 000 in scientific notation,

Dima020 [189]

Answer:

7.49 × 108

Explanation:

Scientific notation is a way to express numbers in a form that makes numbers that are too small or too large more convenient to write. It is commonly used in mathematics, engineering, and science, as it can help simplify arithmetic operations. In scientific notation, numbers are written as a base, b, referred to as the significant, multiplied by 10 raised to an integer exponent, n, which is referred to as the order of magnitude:

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3 years ago

What element has greatest atomic radius from group 3?

stira [4]

Answer:

i think iron

Explanation:

i not sure with my ans

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2 years ago

Consider the following reaction:

NeX [460]

For the given reaction, according to the Law of Conservation of Energy, the energy required to decompose Hcl and produce $H_{2}+c l_{2}$ are equal.

Answer: Option C

<u>Explanation:</u>

According to law of conservation's of energy, energy can only be transferred from reactants to product side. So in this process, it is stated that 185 kJ of energy will be needed to decompose it. So that 185 kJ of energy will be getting transferred to produce the creation of hydrogen and chloride in the product side.

So if we see from the reactants side, the energy of 185 kJ is required for decomposition of hydrogen chloride. Similarly, if we see from the product side, the 185 kJ utilized for decomposition is transferred as energy required to create hydrogen and chlorine atoms. This statement will be in accordance with the law of conservation's of energy.

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3 years ago

Read 2 more answers

The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.

madam [21]

Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

$H_3BO_3\rightarrow H^+H_2BO_3^-$