Answer:
a. H2S(g)/t = 1.48 mol/s
CS2(g)/t = 0.740mol/s
H2(g)/t = 2.96mol/s
b.
Ptot /t = 981torr/min
Explanation:
a. Based on the reaction:
CH4(g) + 2 H2S(g) → CS2(g) + 4 H2(g)
<em>1 mole of CH4 reacts with 2 moles of H2S producing 1 mole of CS2 and 4 moles of 4H2</em>
<em />
If CH4 decreases at the rate of 0.740mol/s, H2S decreases twice faster, that is 0.740mol/s = 1.48 mol/s
CS2 is produced with the same rate of CH4 because 1 mole of CH4 produce 1 mole of CS2 = 0.740mol/s
The H2 is produced four times faster than CH4 is decreased, that is:
0.740mol/s * 4 = 2.96mol/s
b. With the reaction:
2 NH3(g) → N2(g) + 3 H2(g)
2 moles of ammonia are consumed whereas 1 mole of N2 and 3 moles of H2 are produced.
That means 2 moles of gas are consumed and 4 moles of gas are produced.
If the NH3 decreases at a rate of 327torr/min, the gases are produced in a rate twice faster. That is 327torr/min*2 =
654torr/min
The rate of change of the total pressure is rate of reactants + rate of products:
654torr/min + 327torr/min =
981torr/min
Answer:
Atoms are neither created or destroyed.
Explanation:
The end result of a chemical change does not create or destroy any atoms. Matter cannot be created or destroyed, meaning the same amount of atoms exist before and after the change.
Answer:
Percent yield of carbon monoxide is approximately 38%.
Explanation:
Given reaction : C + SiO₂ → Si + CO
On balancing it : 2C + SiO₂ → Si + 2CO
⇒ 2 mole of carbon produces 2 mole of carbon monoxide
or 2×12=24 g of carbon produces 2×(12+16)=56 g of carbon monoxide
⇒ Expected yield of carbon monoxide when 32.5g of carbon is heated with silicon dioxide is 32.5×
⇒ Expected yield = 
= 75.8 g
Actual yield is given as 28.8 g
⇒ The percent yield of carbon monoxide = 
×100
= 
×100
≅<u>38%</u>
Answer: oxygen=2.547g
Explanation:
Based on the question,it was observed that the reaction is reversible
2 moles of KClO3 gives 2 moles of KCl and three moles of O2
Molar mass for KClO3 is 245 g/mol
Molar mass for O2 is 96 g/mol
We are to find the mass of O2 and we Are given the mass KCLO3 is 6.50g
245g of KClO3 gives 96g of O2
6.50g of KClO3 gives xg of O2
Cross multiply
245x=624
X=624/245
X=2.547g
Therefore the gram of oxygen is 2.547g
Answer: a) 
b) 
c) 
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side.
The balanced chemical equations are :
