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frutty [35]
3 years ago
6

PLEASEEEE ANSWER ASAP!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
ozzi3 years ago
8 0

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

The law of conservation of energy states that energy can neither be created nor be destroyed, but it can be transformed from one form to another. So I considered an example of it as follows: water is stored at height with potential energy, the water flows and its potential energy is converted into kinetic energy.

masha68 [24]3 years ago
4 0

Answer:

The law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time .

For example, suppose there is a rock at the top of a hill. It has a lot of potential energy because it is placed at a high point. Next, the rock fall downhill, then it speed increases along the fall (at first it speed was zero), increasing at the same time its kinetic energy while potential energy decrease given that the height of its position decrease. Also some potential and kinetic energy is lost because of friction between the rock and the soil.

As you can see, when some kind of energy is lost another kind of energy/energies increase proportionally, and then the total energy is conserved.

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The light reactions of photosynthesis use _____ and produce _____. The light reactions of photosynthesis use _____ and produce _
SashulF [63]
<h2>Input = NADP^+, water and Output = NADPH + O_2</h2>

Explanation:

The light reactions of photosynthesis use water and produce Oxygen, NADPH.

The equation for photosynthesis :

6 CO_2 + 6 H_2O → C_6H_12O_6 + 6 O_2

The process of photosynthesis in two stages -

  • The first stage is called the light reaction in which the light energy from the sun is captured and converted into chemical energy stored in the form of ATP and NADPH
  • The second stage is the process of conversion of ATP molecules to sugar or glucose (the Calvin Cycle)

For a light reaction -

Net Input is of, NADP^+, Light, Water, ADP

Net Output is of, ATP, NADPH, O_2

8 0
3 years ago
Match the condensed structural diagrams with the correct names
AleksAgata [21]

Answer:

Here's what I get  

Explanation:

1. Names

I.   CH₃-CH₂-COOH              = 49. propanoic acid

II.  CH₃-CH₂-OH                    = 46. ethanol

III. CH₃-COO-CH₂-CH₂-CH₃ = 47. propyl ethanoate

IV. H-O-CH₂-CH₂-CH₃         = 48. propan-1-ol

V.  H-COO-CH₃                    = 51. methyl methanoate

VI. CH₃-COOH                      = 50. ethanoic acid

2. Precursors

52. methyl propionate  ⇒ methanol + propanoic acid

53.   ethyl methanoate ⇒    ethanol + methanoic acid

6 0
3 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
3 years ago
A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X ​
Tasya [4]

\LARGE{ \boxed{  \rm{ \red{Required \: answer}}}}

☃️ Chemical formulae ➝ \sf{CaCO_3}

<h3><u>How to find?</u></h3>

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

\boxed{ \sf{No. \: of \: moles =  \frac{given \: weight}{molecular \: weight} }}

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of \sf{CaCO_3}

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

3 0
4 years ago
Read 2 more answers
Write the condensed nd structural formulas as well as the names for all isomers of C3H5Cl3.
Sergio039 [100]

Answer:

1) 1,1,1-trichloropropane

2) 1,1,2-trichloropropane

3) 1,2,2-trichloropropane

4) 1,2,3-trichloropropane

Explanation:

For this question, we must remember that isomers are molecules that have the <em>same formula but different structure</em>s. For the formula C_3H_5Cl_3 we can draw a <u>linear chain of three carbons</u> and change the position of the chlorine atoms in the carbon chain.

With this in mind, if we put all the chlorine atoms on the same carbon we will get <u>1,1,1-trichloropropane</u>. If we change an atom from chlorine to carbon 2 we will obtain <u>1,1,2-trichloropropane</u>. If we move another chlorine atom to carbon two we will get <u>1,2,2-trichloropropane</u>. Finally, if we put a chlorine atom in each carbon we will obtain <u>1,2,3-trichloropropane</u>.

See figure one for further explanations

I hope it helps!

4 0
4 years ago
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