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3 years ago

I need help with 2 and 3

Mathematics

1 answer:

leonid [27]3 years ago

8 0

The answer for 2 is 320 because you have to keep counting by 40's

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(05.02 LC)

Anvisha [2.4K]

siny=s/8
tany=s/t

$\\ \tt\longmapsto cosy=\dfrac{siny}{tany}$

$\\ \tt\longmapsto cosy=\dfrac{s/8}{s/t}$

$\\ \tt\longmapsto cosy=8/t$

Secy=1/cosy=t/8

7 0

2 years ago

Suppose you were adding 527+405. What would the tens problem be

nydimaria [60]

it would be 3 because when you add it, it gets to be 932 and the tens place is 3.

8 0

3 years ago

In ΔBCD, \overline{BD}

Alex787 [66]

Answer:

30degrees

Step-by-step explanation:

Given

Exterior angle m<CDE = 7x - 19 degrees

interior angles are

m<BCD = 2x - 1

m<DBC = x+10

Since the sum of the interior angles is equal to the exterior, hence;

2x - 1 + x+10 = 7x - 19

3x + 9 = 7x - 19

3x - 7x = -19 - 9

-4x = -28

x = 28/4

x = 7

Get m<CDE

m<CDE = 7x - 19

m<CDE = 7(7) - 19

m<CDE = 49 - 19

m<CDE = 30degrees

4 0

3 years ago

F(x) = -4x2 + 4x – 4 Find f(3)

ValentinkaMS [17]

F(3) occurs when x =3. So lets plug 3 into our equation.

$f(3) = -4(3)^2 + 4(3)-4\\f(3) = -4(9) + 12- 4\\f(3) = -36 + 12- 4\\f(3)= -28$

F(3) = -28

I hope this helps! :)

5 0

3 years ago

Someone help, I suck at math

attashe74 [19]

option A.55°

Answer:

Solution given:

<x+<y=<z

exterior angle of a triangle is equal to the sum of two opposite interior angle

4n-18+n+8=133-6n

5n+6n=133+10

11n=143

n=143/11

n=13

exterior angle =133-6*13=55°

option A.55°

5 0

3 years ago