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Setler79 [48]
3 years ago
14

Jillian tracks her progress on her spelling test over a period

Mathematics
2 answers:
klemol [59]3 years ago
7 0
What's the question?
Alex_Xolod [135]3 years ago
3 0

Answer:

What is your question?

Step-by-step explanation:

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Find the midpoint of the line segment joining the points ​(-1​,​-1) and ​(-3​,​12).
gregori [183]

Answer:

(-2, 11/2)

Step-by-step explanation:

use the mid-point formula!

((x1+x2)/2, (y1+y2)/2)

((-1+-3)/2, (-1+12)/2)

(-2, 11/2)

8 0
3 years ago
Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that
Bond [772]

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }

.

.

.

Following the pattern, we can see that for f^{n}(x),

f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} }  \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}

This applies for n ≥ 1, Expressing f(x) in summation, we have

\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}

Combining ln2 with the rest of series, we have

f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Taylor series is f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2}  }

Find out more information about taylor series here

brainly.com/question/13057266

#SPJ4

3 0
1 year ago
Find the indicated function values for the function below<br> g(x)=9x + 8<br> g(0) =
Dennis_Churaev [7]

Answer:

g(0) = 8

Step-by-step explanation:

The problem gives us the following function:

g(x) = 9x + 8

g(0) =

This is the value of g when x = 0. So

g(x) = 9x + 8

g(0) = 9*0 + 8

g(0) = 8

So the answer to this question is:

g(0) = 8

6 0
3 years ago
Hurry :(
Naya [18.7K]

Answer:

The answer is d=37 in

Step-by-step explanation:

3 0
3 years ago
Find the quotient:<br> -35x3-10x<br> 5x
miv72 [106K]
The quotient if the equation is x3
5 0
2 years ago
Read 2 more answers
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