Let
x------------> <span>the flags length
</span>y------------> the flags <span>width
P----------> perimeter
we know that
p=2x+2y------> 2x+2y=560----------> equation 1
and
x=y+40-------------> equation 2
</span> substitute 2 in 1<span>
2*(y+40)+2y=560-----------> 2y+80+2y=560--------> 4y=480------> y=120
x=y+40-------> 120+40----------> x=160
the answer is
</span>
the flags length is 160 ftthe flags width is 120 ft
Part 2) Write three
situation to which you could apply the resulting system of equations 1) It can be used when considering the relationship between the price of a product and the quantities of the product that people want to buy at a certain price.
2) It can be used to determine the speed, distance and time duration when traveling by car, and you want to know the values of the unknown variables in your trips.
3) It can be used to determine the most convenient loan option to buy a car or a house when considering the duration of the loan.
If I counted correctly, the answer would be 52/150. You just need to simplify the fraction. I'll recount soon, and update if it changes.
The probability of picking a ticket that is green or has a number greater than four is 3/5
<h3>How to determine the probability?</h3>
The given parameters are:
Yellow = 1 - 5
Green = 1 - 5
Total = 10
There are 2 cards whose numbers are greater than 4 i.e. Yellow 5 and Green 5
So, we have:
P(Number greater than 4) = 2/10
There are 5 green cards.
So, we have:
P(Green) = 5/10
Also, 1 green card is numbered greater than 4
So, we have:
P(Green greater than 4) = 1/10
The required probability is:
P = P(Green) + P(Number greater than 4) - P(Green greater than 4)
This gives
P = 5/10 + 2/10 - 1/10
Evaluate
P = 6/10
Simplify
P =3/5
Hence, the probability of picking a ticket that is green or has a number greater than four is 3/5
Read more about probability at:
brainly.com/question/11234923
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9514 1404 393
Answer:
a. 0.6 h
b. 1.3 h
c. C -- No
d. 4.2 mi/h
Step-by-step explanation:
a. The relationship between time (t), speed (s), and distance (d) is ...
t = d/s
The time spent running 4 miles at 7 miles per hour is ...
t = (4 mi)/(7 mi/h) = (4/7) h ≈ 0.6 h
__
b. The time spent walking home is ...
t = (4 mi)/(3 mi/h) = 4/3 h ≈ 1.3 h
__
c. C -- No, less time is spent at 7 mi/h
__
d. The average speed is ...
s = d/t = (4 mi +4 mi)/(4/7 h +4/3 h) = (8 mi)/(40/21 h) = 4.2 mi/h