1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Liula [17]
3 years ago
8

This is 1 day late- help. ASAP

Mathematics
2 answers:
White raven [17]3 years ago
7 0

Answer:

the third option

Step-by-step explanation:

do you want an explanation?

Sliva [168]3 years ago
3 0
The answer to this question is x=5
You might be interested in
Let f(x) = .............
galben [10]

Answer:

4

Step-by-step explanation:

g(3) = -2(3)^2 -4 = 2(9) -4 = 18-4 = 14

|f(2)| = | 2^2 -3| = | 4-3| = 1

(g(3) +2) = (14+2) = 16

4*  |f(2)|  = 4*1 = 4

16/4 = 4

5 0
3 years ago
Please help me with this one
Nesterboy [21]

Answer:

240

Step-by-step explanation:

well do *

so 8x6x5 = 240 there's your answer

3 0
3 years ago
Read 2 more answers
The midpoint of AB = ([?],[ ])
3241004551 [841]

Answer:

(0,0)

Step-by-step explanation:

x_{m}=\frac{-2+2}{2}=0\\y_{m}=\frac{-2+2}{2}=0\\

4 0
3 years ago
We are learning about angle
neonofarm [45]

Answer:

Step-by-step explanation:

If you cut the square apart along a diagonal, you'll then have two isosceles triangles.  Each such triangle will have 3 sides and 3 angles.  

Next time, please type in a more descriptive title for your question.

7 0
3 years ago
The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and
strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

                                   X ~ N ( u , s /√n )

Where

                            s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

                        P ( 5 < X < 10 ) = P (    (5 - 8) / 0.2143 <  Z  <  (10-8) / 0.2143   )

                                                 = P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

                        P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1        

7 0
2 years ago
Other questions:
  • Why is the use of existing data, especially in comparative and historical research, especially helpful to students?
    5·1 answer
  • When solving a word problem, what step should you always do after reading the problem, but prior to writing the equation?
    12·1 answer
  • Help with this word problem
    5·1 answer
  • 5(x+3)−2x Which expression correctly combines the like terms? 3x+15 3x+3 3x2+15 3x2+3
    15·1 answer
  • Which mixed number correctly describes the shaded area of the fraction bars? 2One-half 2Two-sixths 2Two-fifths 3
    12·1 answer
  • ▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓
    8·2 answers
  • A mirror with a parabolic cross section is used to collect sunlight on a pipe located at the focus of the mirror. The pipe is lo
    7·1 answer
  • Use the distributive property to multiply.<br><br> -(-16m-1)
    11·1 answer
  • A company has offices in two different countries. Employee salaries at both locations are strongly skewed
    14·1 answer
  • Dean had 30 toy whistles.
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!