Answer:
Q2) A 0.5//// B 0.11//// C 1.7//// D 1.15//// E 2.13//// F 4.1
Answer:
![x = - 2](https://tex.z-dn.net/?f=x%20%3D%20%20-%202)
The answer would be -2 you may look at my work to see how I solved it
Answer:
<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
- First we need to convert the equation into ax+by+c=0 form
![\sf 5y=15x-90](https://tex.z-dn.net/?f=%5Csf%205y%3D15x-90%20)
![\longrightarrow](https://tex.z-dn.net/?f=%5Clongrightarrow)
![\sf 15x-90-5y=0](https://tex.z-dn.net/?f=%5Csf%2015x-90-5y%3D0%20)
![\longrightarrow](https://tex.z-dn.net/?f=%5Clongrightarrow)
![\sf 15x-5y-90=0](https://tex.z-dn.net/?f=%5Csf%2015x-5y-90%3D0%20)
- Now compare with ax+by+c=0
- We get
- ax=15x
- by=-5y
- c=-90
<h3>Hence the values are </h3>
![\sf a=15 \\ \sf b=-5 \\ \sf c=-90](https://tex.z-dn.net/?f=%5Csf%20a%3D15%20%5C%5C%20%5Csf%20b%3D-5%20%5C%5C%20%5Csf%20c%3D-90%20)
Answer:
- BC = 6
- x = 5
- CE = 16
- Yes, BC║DE
Step-by-step explanation:
1. The parallel lines make the various triangles similar, so the corresponding sides are in proportion.
... BC/AB = FE/A.F
... BC/9 = 4/6
... BC = 9·4/6 = 6
2. As in problem 1, the triangles are similar, so ...
... x/(x+10) = 10/30
... 30x = 10x + 100 . . . . multiply by 30(x+10)
... 20x = 100 . . . . . . . . . subtract 10x
... x = 100/20 = 5
3. As in problems 1 and 2, the triangles are similar, so ...
... AD/DB = CE/EB
... 24/27 = CE/18
... 18·24/27 = CE = 16
4. If the lines of interest are parallel, the triangles will be similar and corresponding measures will be in proportion.
Compare AD/DB = 15/12 = 5/4 to AE/EC = 10/8 = 5/4. These are equal, so corresponding measures are proportional. Therefore we conclude the triangles are similar and BC║DE.