Answer:
a. Plan B; $4
b. 160 mins; Plan B
Step-by-step explanation:
a. Cost of Plan A for 80 minutes:
Find 80 on the x axis, and trave it up to to intercept the blue line (for Plan A). Check the y axis to see the value of y at this point. Thus:
f(80) = 8
This means Plan A will cost $8 for Rafael to 80 mins of long distance call per month.
Also, find the cost per month for 80 mins for Plan B. Use the same procedure as used in finding cost for plan A.
Plan B will cost $12.
Therefore, Plan B cost more.
Plan B cost $4 more than Plan A ($12 - $8 = $4)
b. Number of minutes that the two will cost the same is the number of minutes at the point where the two lines intercept = 160 minutes.
At 160 minutes, they both cost $16
The plan that will cost less if the time spent exceeds 160 minutes is Plan B.
3 times 7= 21 times three =63
Answer:
Area = 24 in²
Perimeter = 24in
Step-by-step explanation:
To find the area given the length of the 3 sides:
a= 8in
b= 6.4in + 3.6in= 10in
c= 6in
Add them together:
8in + 10in + 6in
= 24in²
To find the perimeter you do the same thing:
a= 8in
b= 10in
c= 6in
Add them together
=24in
DO <u>NOT</u> SQUARE THE ANSWER WHEN FINDING <u>PERIMETER</u>
The bag contains,
Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,
Total marbles (possible outcome) is,

Let P(R) represent the probablity of picking a red marble,
P(G) represent the probability of picking a green marble and,
P(B) represent the probability of picking a blue marble.
Probability , P, is,


Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,
That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

Hence, the best option is G.