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Flauer [41]
4 years ago
6

Need help on simplifying this

Mathematics
1 answer:
Alex73 [517]4 years ago
7 0
X-1/x is the answer you need for this

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A regulation nfl football field of length x and width y have a perimeter of 1040/3. What is the equation for width
quester [9]
The shape of the field is rectangle 
The perimeter of a rectangle is the total length of all four borders.

x + x + y + y = 1040/3 ⇒ Collecting like term
2x + 2y = 1040/3 ⇒ We want to isolate 'y', so move '2x' to the right hand side of equation

2y = 1040/3 ÷ 2x
y = \frac{1040/3}{2x} ÷ 2
y = 1040/12x

6 0
3 years ago
Olivia paid 13.75 for a puzzle that amount included 8% sales tax round to the nearest cent how much did the puzzle cost before t
VikaD [51]
The answer would be $12.65
3 0
3 years ago
Read 2 more answers
Try to create a triangle with angle measures 20°, 50°, and 80°. Which of the following describes the figure?
antiseptic1488 [7]

Answer:

it is a triangle whose sides appear to be all different lengths

8 0
3 years ago
Joy recorded the distances she walked each day for five days. How far did she walk in 5 days?
oee [108]

Joy walked 1/3 units (miles? kilometers? it doesn't matter actually) in 3 of the 5 days. So, walking 1/3 units for three days tallies up to

\dfrac{1}{3}\cdot 3 = 1

If we add the day when she walked 1/2 units and the day she walked 2/3 units, we get

1+\dfrac{1}{2}+\dfrac{2}{3} = \dfrac{6+3+4}{6} = \dfrac{13}{6}

3 0
3 years ago
Using an absolute-value inequality, describe the set of numbers whose distance from 4 is greater than 5 units. Draw a graph of t
Aleks04 [339]

The solution to the absolute-value inequality is x > 9; and x < -1

<h3>What is an inequality?</h3>

An inequality is an expression that shows the nonequal comparison of two or more numbers and variables.

Let x represent the unknown number, hence:

|x - 4| > 5

(x - 4) > 5; and -(x - 4) > 5

x > 9; and x < -1

The solution to the absolute-value inequality is x > 9; and x < -1

Find out more on inequality at: brainly.com/question/24372553

3 0
2 years ago
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