if you look at the part where the first part connects with the second part:
y = 5 if x < - 2
y = -2x + 1 if -2 ≤ x < 1
we don't have a discontinuity there, so there shouldn't be a dot.
<h3>
</h3><h3>
What is wrong with the graph?</h3>
When we graph over intervals like (a, b) or [a, b] or something like that, we use dots to define the end of the intervals, and to denote that the function ends abruptly or we have a jump.
In this case, you can see that between the end and the second part and the beginning of the third part there is a jump, so the use of dots is correct there, but if you look at the part where the first part connects with the second part:
y = 5 if x < - 2
y = -2x + 1 if -2 ≤ x < 1
we don't have a discontinuity there, so there shouldn't be a dot.
That is the only error with the graph.
If you want to learn more about piecewise functions:
brainly.com/question/3628123
#SPJ1
Answer:
2x(30+8-6)-20
Step-by-step explanation:
Answer:
chisquare = 31.667
degree of freedom = 2
Step-by-step explanation:
Formula for chisquare test = (O-E)²/E
total number observations= 60 + 25 + 15 = 100
Estimated E,
80% x 100 = 80
15%x100 = 15
5% x 100 = 5
chisquare =
= 5 + 6.67 + 20
= 31.667
from the calculation above the value of the chisquare statistic = 31.67
the degree of freedom is the number of samples in the test n - 1
= 3-1
= 2
I have solve this question also in a tabular form to aid understanding in the file i uploaded.
thank you and good luck!
Answer:
4743246
Step-by-step explanation:
Answer:
The answer to your question is 10 dm
Step-by-step explanation:
Data
length of a rectangle = x + 4
height of a rectangle = x - 6
Area of the rectangle = 56 dm²
length of the square = x
Process
1.- Find x with the information given for the rectangle
Area = length x height
Substitution
56 = (x + 4)(x - 6)
Expand
56 = x² - 2x - 24
Equal to zero
x² - 2x - 24 - 56 = 0
Simplify
x² - 2x - 80 = 0
Factor
(x - 10)(x + 8) = 0
Equal to zero
x₁ -10 = 0 x₂ + 8 = 0
x₁ = 10 x₂ = -8
2.- Conclusion
The length of the square is 10 dm because there are no negative lengths.
