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2 years ago

Find the circumference of a circle whose area is equal to 64π^2

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

7 0

Answer:

14 6/7 is the circumference

Step-by-step explanation:

you first of all look for the radius using the formulae multiply both sides by the reciprocal of 22/7

7/22 ×22/7r=64×7/22=224/11{2 4/11)

2 4/11 is the radius

cir =2×22/7×2 4/11

2×22/7× 26/11=104/7

==== =14 6/7

all i can do but am not sure sorry

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3 years ago

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Answer:

1) The factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) The factors of $x^2+2x-8=0$ are $\mathbf{(x-2)(x+4)=0}$

Option B is correct.

Step-by-step explanation:

1) Factor : $x^2-3x+2=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : -3x

We can break them as (-2x)( -x)

Solving:

$x^2-3x+2=0\\x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0$

So, factors of $x^2-3x+2=0$ are $\mathbf{(x-1)(x-2)=0}$

Option C is correct.

3) Factor: $x^2+2x-8=0$

For factoring we need to break the middle term, such that there sum is equal to middle term of expression and product is equal to product of first and last term.

The middle term : 2x

We can break them as (4x)( -2x)

Solving

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Option B is correct.

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3 years ago

Find the circumference of a circle whose area is equal to 64π^2​

Find the circumference of a circle whose area is equal to 64π^2