Step-by-step explanation:
Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC
To prove = ∠3= 49°
Solution:
In figure, m∥n cut by traversal t.
So, ∠DEF = ∠ABC(alternative exterior angles)
∠1 + ∠2 = ∠4 + ∠5
∠ABC = ∠1 + ∠2 = 50° + 48° = 98°
Also given that s bisect angles ∠ABC.
∠4 = ∠5
∠ABC = ∠4 + ∠5 = 98°
∠4 + ∠4 = 98°
2∠4 = 98°
∠4 = 49°
∠4= ∠3 = 49° (vertically opposite angles)
∠3 = 49° ,hence proved
1.79 + 1.29 if i’m understanding the question right
that would be 3.08
So you foil out the problem and get
