Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average

Question

3 years ago

14

Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average

speed of 20 miles per hour. The entire two-part, 15-mile race took him 1.125 hours to complete. Which table correctly represents his rates, times, and distances for each part of the race?

Mathematics

2 answers:

yulyashka [42] · Answer 1 · 2022-08-08T22:12:17+03:00

yulyashka [42]3 years ago

7 0

Answer:

A.

Step-by-step explanation:

lutik1710 [3] · Answer 2 · 2022-08-08T20:43:57+03:00

Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5

Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.