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3 years ago

5. 1.00 mol HNO3 is treated with 4.47 g of magnesium. Calculate the number of moles of

Chemistry

1 answer:

ruslelena [56]3 years ago

3 0

Answer:

The balanced equation is:

2 HNO3 + Mg ---> Mg(NO3)2 + H2

From the equation, we can see that we need twice the moles of HNO3 than the moles of Mg

Moles of Mg:

Molar mass of Mg = 24 g/mol

Moles = Given mass / Molar Mass

Moles of Mg = 4.47 / 24 = 0.18 moles (approx)

Hence, 2(moles of Mg) = 0.36 moles of HNO3 will be consumed

Number of moles of HNO3 after the reaction is finished is the number of unreacted moles of HNO3

Unreacted moles of HNO3 = Total Moles - Moles consumed

Unreacted moles of HNO3 = 0.64 moles (approx)

Since we approximated the value of moles of Mg, the value of remaining moles of HNO3 will also be approximate

From the given options, we can see that 0.632 moles is the closest value to our answer

Therefore, 0.632 moles will remain after the reaction

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Glucose, C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the equation C

Crank

Answer:

70.3824 grams of carbondioxide is produced.

Explanation:

$C_6H_{12}O_6(aq)+6O_2(g)⟶6CO_2(g)+6H_2O(l)$

Moles of glucose = $\frac{48.0 g}{180 g/mol}=0.2666 mol$

According to reaction 1 mole of glucose reacts with 6 mole of oxygen gas.

Then 0.2666 mol of gluocse will reactwith :

$\frac{6}{1}\times 0.2666 mol =1.5996 mol$ of oxygen

Mass of 1.5996 moles of oxygen gas:

$1.5996 mol\times 32 g/mol = 51.1872 g$

51.1872 grams of oxygen are required to convert 48.0 grams of glucose to $CO_2$ and $H_2O$ .

According to reaction, 1 mol, of glucose gives 6 moles of carbon dioxide.

Then 0.2666 moles of glucose will give:

$\frac{6}{1}\times 0.2666 mol =1.5996 mol$ of carbon dioxide

Mass of 1.5996 moles of carbon dioxide gas:

$1.5996 mol\times 44 g/mol = 70.3824 g$

70.3824 grams of carbondioxide is produced.

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3 years ago

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A, C, B