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2 years ago

A solution of pH 3 was mixed with a solution of pH 9. What is the final pH could be ?

Chemistry

1 answer:

chubhunter [2.5K]2 years ago

3 0

The solution of which contains of PH 3 called acidic medium which is more stronger acid called HCl when reacts to the stronger base base NaOH forms the acid base reaction .

According to acid base equation you consider ph5 as PH 9 if you understand it then tell me below

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Barbara is conducting an experiment to observe heat flow. She places one piece of metal in a freezer at -18 degrees Celsius (°C)

yulyashka [42]

Answer: The correct answer is heat will flow from the boiling water into the frozen metal.

Explanation:

According to the law of conservation of energy, energy cannot be destroyed nor created but it can be transformed from 1 form to another form.

There are 3 processes of heat transfer:

Conduction: This type of heat transfer occurs when there is direct contact between the two objects.
Convection: This type of heat transfer occurs when there is a movement of fluid (liquid or gas) due to the movement of hot layers to the top and cold layers to the bottom which leads to convection currents.
Radiation: This type of heat transfer occurs when there is a direct transfer of energy through space.

The heat moves from a hot surface to a cold surface to maintain equilibrium.

We are given:

A metal is placed in a freezer (cold object) and another metal is placed in an oven (hot object) and then both the metals are placed in boiling water.

Initially, the heat will flow from the boiling water (hot object) into the frozen metal (cold object) to maintain equilibrium

Hence, the correct answer is heat will flow from the boiling water into the frozen metal.

4 0

3 years ago

A sample of gas has a volume of 400 liters when its temperature is 20.C and its pressure

ikadub [295]

Answer:

V₂ = 145.35 L

Explanation:

Given data:

Initial volume = 400 L

Initial pressure = 300 mmHg (300/760 =0.39 atm)

Initial temperature = 20 °C (20 +273 = 293 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂ /T₁ P₂

V₂ = 0.39 atm × 400 L × 273 K / 293 K × 1 atm

V₂ = 42588 atm.L.K /293 K.atm

V₂ = 145.35 L

5 0

2 years ago

the spectral lines observed for hydrogen arise from transitions from excited states back to the n=2 principle quantum level. Cal

Sunny_sXe [5.5K]

Rydberg formula is given by:

$\frac{1}{\lambda } = R_{H}\times (\frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} )$

where, $R_{H}$ = Rydberg constant = $1.0973731568508 \times 10^{7} per metre$

$\lambda$ = wavelength

$n_{1}$ and $n_{2}$ are the level of transitions.

Now, for $n_{1}$ = 2 and $n_{2}$ = 6

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{6^{2}} )$

= $1.0973731568508 \times 10^{7} \times (\frac{1}{4}-\frac{1}{36} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.0278 )$

= $1.0973731568508 \times 10^{7} \times 0.23$

= $0.2523958\times 10^{7}$

$\lambda = \frac{1}{0.2523958\times 10^{7}}$

= $3.9620\times 10^{-7} m$

= $396.20\times 10^{-9} m$

= $396.20 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 5

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{5^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.04 )$

= $1.0973731568508 \times 10^{7} \times (0.21 )$

= $0.230 \times 10^{7}$

$\lambda= \frac{1}{0.230 \times 10^{7}}$

= $4.3478 \times 10^{-7} m$

= $434.78\times 10^{-9} m$

= $434.78 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 4

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{4^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.0625 )$

= $1.0973731568508 \times 10^{7} \times (0.1875 )$

= $0.20575 \times 10^{7}$

$\lambda= \frac{1}{0.20575 \times 10^{7}}$

= $4.8602 \times 10^{-7} m$

= $486.02 \times 10^{-9} m$

= $486.02 nm$

Now, for $n_{1}$ = 2 and $n_{2}$ = 3

$\frac{1}{\lambda} = 1.0973731568508 \times 10^{7} \times (\frac{1}{2^{2}}-\frac{1}{3^{2}} )$

= $1.0973731568508 \times 10^{7} \times (0.25-0.12 )$

= $1.0973731568508 \times 10^{7} \times (0.13 )$

= $0.1426585\times 10^{7}$

$\lambda= \frac{1}{0.1426585\times 10^{7}}$

= $7.0097 \times 10^{-7} m$

= $700.97 \times 10^{-9} m$

= $700.97 nm$

5 0

2 years ago

Read 2 more answers

4. Distinguish where kinetic energy and potential energy are the greatest in the loop.

aksik [14]

Kinetic energy is the energy from movement. Hence the fastest movement is at the bottom of the loop - therefore Kinetic energy is highest at the flat bottom of the loop.

Potential energy is the opposite - it occurs at the top of the loop when the car moves the slowest

4 0

2 years ago

A scientist plants two rows of corn for experimentation. She puts fertilizer on row 1 but does not put fertilizer on row 2. Both

IrinaVladis [17]

Answer:

Q9. The independent variable in this experiment is the fertilizer. It is independent because she manipulating the variable to compare the growth.

Q10. The dependent variable in this experiment is the amount of growth of the corn. It is this because the growth depends on what the scientist did on the corn.

Q11. The variable controlled in this experiment is the amount of sun and water. These two variables never change so this is why it is the control.

Explanation:

5 0

2 years ago

Read 2 more answers