Ask question

Ask question

All categories

2 years ago

6

A solution of pH 3 was mixed with a solution of pH 9. What is the final pH could be ?

1 answer:

chubhunter [2.5K]2 years ago

3 0

The solution of which contains of PH 3 called acidic medium which is more stronger acid called HCl when reacts to the stronger base base NaOH forms the acid base reaction .

According to acid base equation you consider ph5 as PH 9 if you understand it then tell me below

You might be interested in

Using the formula M1V1 = M2V2 , how many milliliters of a 2. 50 M hydrochloric acid solution is required to make 100. 0 mL of a

gladu [14]

Dilution of the solution can be calculated by the formula of the molarity and volume. The initial volume of 2.50 M solution was 30 mL.

<h3>What is the relationship between molar concentration and dilution?</h3>

Molar concentration or the dilution factor is in an inverse relationship and with an increase in the dilution, the molarity of the solution decreases.

Given,

Initial molarity = 2.50 M

initial volume = ?

Final molarity = 0.750 M

Final volume = 100.0 ml

Substituting values in the formula:

$\begin{aligned}\rm V_{1} &= \rm \dfrac{M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.750 \times 100}{2.50}\\\\&= 30 \;\rm mL\end{aligned}$

Therefore, 30 mL was the initial volume of the solution before it was diluted.

Learn more about dilution here:

brainly.com/question/26896011

3 0

2 years ago

What's the electron configuration of an N⁻³ ion

tatuchka [14]

The electronic configuration of n - 3 ion is [He] 2s2 2p3.

5 0

1 year ago

Part G Wavelength is the distance between the crests (tops) or the troughs (bottoms) of two waves that are next to each other. N

Vlada [557]

Answer: 4.4

Explanation:

Thats what my computer says after i submit answer

3 0

2 years ago

A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C

Romashka [77]

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}$

$Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor. ${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= charge for charged species , For $Ca^{2+}$ , n =2

${\text{Equivalent weight}}=\frac{40}{2}=20g$

$\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents$

$Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L$

Thus there will be 0.00002 meq per Liter of the solution.

3 0

3 years ago

Which can be used to determine the H?

mamaluj [8]

F,g,a can be used to get ''h''

8 0

2 years ago

Read 2 more answers