How much Cu-61 (half-life about 3 hours) would remain from a 2 mg sample after 9 hours?
1 answer:
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Explanation:
1)
Mass of NaOH = m
MOlar mass of NaOH = 40 g/mol
Volume of NaOH solution = 1.00 L
Molarity of the solution= 1.00 M
A student can prepare the solution by dissolving the 40. grams of NaOH in is small volume of water and making that whole volume of solution to volume of 1 L.
Upto two significant figures mass should be determined.
2)
(dilution equation)
Molarity of the NaOH solution =
Volume of the solution =
Molarity of the NaOH solution after dilution =
Volume of NaOH solution after dilution=
A student can prepare NaOH solution of 1.00 M by diluting the 0.500 L of 2.00 M solution of NaOH with water to 1.00 L volume.
Upto three significant figures volume should be determined.
Answer:
Explanation: The strengths of the inter molecular forces varies as follows -
The normal boiling point of CSe2 is 125°C and that of CS2 is 116°C, which explains the trend that as we move down the group, the boiling point of e compound increases as the size increases.
This usually happens because larger and heavier atoms have a tendency to exhibit greater inter molecular strengths due to the increase in size . As the size increases, the valence shell electrons move far away from the nucleus, thus has a greater tendency to attract the temporary dipoles.
And larger the inter molecular forces, more tightly the electrons will be held to each other and thus more thermal energy would be required to break the bonds between them.
Answer:
<h3>The answer is 4.15 g/mL</h3>Explanation:
The density of a substance can be found by using the formula
From the question
mass of object = 8.3 g
volume = final volume of water - initial volume of water
volume = 8 - 6 = 2 mL
So we have
We have the final answer as
<h3>4.15 g/mL</h3>Hope this helps you