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Olegator [25]
2 years ago
11

The conversion of acetyl chloride to methyl acetate occurs via the following two-step mechanism: Reaction sequence of acetyl chl

oride to methyl acetateAccess the text alternative for PROBLEMS Kinetics and Rate Laws 6.49. Add curved arrows to show the movement of the electrons in each step. Write the rate equation for this reaction, assuming the first step is rate-determining. If the concentration of were increased 10 times, what would happen to the rate of the reaction? If the concentrations of both and were increased 10 times, what would happen to the rate of the reaction? Classify the conversion of acetyl chloride to methyl acetate as an addition, elimination, or substitution.
Chemistry
1 answer:
Svetlanka [38]2 years ago
4 0

If the concentration of acetyl chloride  is increased ten times the rate of reaction is increased ten times.

The conversion of acetyl chloride to methyl acetate is a substitution reaction. Recall that a substitution reaction is one in which a moiety in a molecule is replaced by another.

In this reaction, the CH3O- ion replaces the chloride ion. In the first step, the CH3O- ion attacks the substrate in a slow step. This creates a tetrahedral intermediate. Loss of the chloride ion yields the  methyl acetate product.

The rate determining step is the formation of the tetrahedral intermediate. Since the reaction is first order in the acetyl chloride, if its concentration is increased ten times the rate of reaction is increased ten times.

Learn more: brainly.com/question/5624100

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If you place 1.0 L of ethanol (C2H5OH) in a small laboratory that is 3.0 m long, 2.0 m wide, and 2.0 m high, will all the alcohol evaporate? If some liquid remains, how much will there be? The vapor pressure of ethyl alcohol at 25 °C is 59 mm Hg, and the density of the liquid at this temperature is 0.785g/cm^3 .

will all the alcohol evaporate? or none at all?

Answer:

Yes, all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore  be zero.

Explanation:

Given that:

The volume of alcohol which is placed in a small laboratory = 1.0 L

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Converting 59 mmHg to atm ; since 1 atm = 760 mmHg;

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= \frac{59}{760}atm

= 0.078 atm

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Density of the ethanol = 0.785 g/cm³

The volume of laboratory = l × b × h

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= 15 m³

Converting the volume of laboratory to liter;

since 1 m³ = 100 L; Then, we  have:

15 × 1000 = 15,000 L

Using ideal gas equation to determine the moles of ethanol in vapor phase; we have:

PV = nRT

Making n the subject of the formula; we have:

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n = \frac{0.078 * 15000}{0.082*290}

n = 47. 88 mol of ethanol

Moles of ethanol in 1.0 L bottle can be calculated as follows:

Since  numbers of moles = \frac{mass}{molar mass}

and mass = density × vollume

Then; we can say ;

number of moles = \frac{density*volume }{molar mass of ethanol}

number of moles =\frac{0.785g/cm^3*1000cm^3}{46.07g/mol}

number of moles = \frac{&85}{46.07}

number of moles = 17.039 mol

Thus , all the ethanol present in the laboratory will evaporate since the mole of ethanol present in vapor is greater. The volume of ethanol left will therefore be zero.

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2 years ago
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This is why the following equation is incomplete:

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