Question

Anyone able to help me out? I don’t really understand this. Question 5&6

Answer 1

Answer:

  5. 200/1 = 200 ft/min

  6. 600/3 = 200 ft/min

Step-by-step explanation:

5. The rate of change of a graph is the ratio of vertical change to horizontal change. You are asked to find the rate of change from 1 minute to 2 minutes, so you want to find the distance (ft) at 2 minutes and at 1 minute.

Reading the graph, you see that at 2 minutes, the distance is 400 ft. At 1 minute, it is 200 ft.

So, the ratio of the two differences is ...

  change in distance / change in time

  $=\dfrac{400-200}{2-1}=\dfrac{200}{1}=200\quad\text{ft per min}$

__

6. Using the same idea, we want to use the graph values at 4 minutes and 1 minute.

  $\dfrac{\text{ \Delta distance}}{\text{ \Delta time}}=\dfrac{800-200}{4-1}=\dfrac{600}{3}=200\quad\text{ft per min}$