Answer:
The length of the segment AB is 18.8 cm or 1.88 dm
Step-by-step explanation:
<u><em>The question in English is</em></u>
Points A, B and C are collinear in this order. Find the length of the segment: a) AB, if AC = 20 cm, BC = 0.12 dm
we have that
----> by Addition segment postulate
substitute the given values in centimeters
Remember that

so


solve for AB

Convert to dm

therefore
The length of the segment AB is 18.8 cm or 1.88 dm
To do these, start by looking at the "b" value -6.
divide it by 2
-6/2 = -3
now square this number
(-3)^2 = 9
this is what you need for the "c" value
there is only a 5 for the c value so add 4 to both sides of the equation. ( +4 = +4)
y +4 = x^2 -6x +5 +4
y +4 = x^2 -6x +9
y +4 = (x -3)^2
y = (x -3)^2 - 4
vertex ( 3, -4) upwards facing like a bowl, because the "a" value is positive. So the vertex is the minimum, lowest point on the graph.

The value of
.


We know that,

➪ 125° +
+ 30° = 180°
➪
+ 155° = 180°
➪
= 180° - 155°
➪
= 25°
Therefore, the value of
is 25°.
Now, the three angles of the triangle are 125°, 25° and 30°.

✒ 125° + 25° + 30° = 180°
✒ 180° = 180°
✒ L. H. S. = R. H. S.


Answer:
770000
Step-by-step explanation:
im not sure
Answer: 2
Steps:
f(-2) = 1/2x^2
f(-2) = 1/2(-2)^2
f(-2) = 1/2(4)
f(-2) = 2