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ozzi
3 years ago
9

Simplify the expression. [2×(10+5)]-5

Mathematics
1 answer:
svetlana [45]3 years ago
3 0
<span>[2×(10+5)]-5
[2*15]-5
30-5
25</span>
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Which triangle is a 30° -60° -90° triangle?
Fittoniya [83]

Answer:

Acute isosceles triangle

Step-by-step explanation:

because an acute angle is more than 45 but less then 90.

that's all i know sorry!

5 0
3 years ago
The sum of two consecutive integers is at least 185. what is the smaller of the two integers? enter your answer in the box.
ss7ja [257]
Let us assume the first integer to be = x
Then
The second integer will be = x + 1
The sum of the two consecutive integers =185
Then
x + x + 1 = 185
2x + 1 = 185
2x = 184
x = 92
From the above deduction, we can easily conclude that the smallest of the two integers is 92. I hope that the answer has helped you.
4 0
3 years ago
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Can someone give me some tips of how to study. I have already tried writing everything in my lesson but it doesn't seem to work
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Study all notes, reread the chapters again. Have someone ask questions on the chapters page by page. This always has worked for me. Plus try to do this again the night before the test. You will be surprised how much you can remember by doing it again the night before the test. Hope this helps.
8 0
3 years ago
Question is attached answer asap. Will give brainliest
schepotkina [342]
1.) (-2,3)
2.) a=175/43 b= -70/43
3.)(7,3)

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3 years ago
How to do graphs of quadratic functions ​
Anastaziya [24]

Answer:

The Graph of a Quadratic Function

A quadratic function is a polynomial function of degree 2 which can be written in the general form.

Step-by-step explanation:

Example: Graph: f(x)=−x2−2x+3.

Solution:

Step 1: Determine the y-intercept. To do this, set x=0 and find f(0).

f(x)f(0)===−x2−2x+3−(0)2−2(0)+33

The y-intercept is (0,3).

Step 2: Determine the x-intercepts if any. To do this, set f(x)=0 and solve for x.

f(x)000x+3x======−x2−2x+3−x2−2x+3x2+2x−3(x+3)(x−1)0−3orx−1x==Set f(x)=0.Multiply both sides by −1.Factor.Set each factor equal to zero.01

Here where f(x)=0, we obtain two solutions. Hence, there are two x-intercepts, (−3,0) and (1,0).

Step 3: Determine the vertex. One way to do this is to first use x=−b2a to find the x-value of the vertex and then substitute this value in the function to find the corresponding y-value. In this example, a=−1 and b=−2.

x====−b2a−(−2)2(−1)2−2−1

Substitute −1 into the original function to find the corresponding y-value.

f(x)f(−1)====−x2−2x+3−(−1)2−2(−1)+3−1+2+34

The vertex is (−1,4).

Step 4: Determine extra points so that we have at least five points to plot. Ensure a good sampling on either side of the line of symmetry. In this example, one other point will suffice. Choose x=−2 and find the corresponding y-value.

x −2  y 3f(−2)=−(−2)2−2(−2)+3=−4+4+3=3Point(−2,3)

Our fifth point is (−2,3).

Step 5: Plot the points and sketch the graph. To recap, the points that we have found are

y−intercept:x−intercepts:Vertex:Extra point:(0,3)(−3,0) and (1,0)(−1,4)(−2,3)

Answer:

4 0
2 years ago
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